Timeline for Inverse regex in AWK?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 15, 2023 at 11:52 | answer | added | RARE Kpop Manifesto | timeline score: 0 | |
| Mar 3, 2022 at 13:01 | answer | added | adamency | timeline score: 3 | |
| Sep 29, 2018 at 3:44 | history | edited | slm♦ | CC BY-SA 4.0 | deleted 5 characters in body; edited title |
| Oct 25, 2016 at 17:29 | answer | added | DopeGhoti | timeline score: 19 | |
| Oct 25, 2016 at 17:11 | history | edited | ilkkachu | CC BY-SA 3.0 | deleted 118 characters in body |
| Oct 25, 2016 at 16:41 | comment | added | Sundeep | but why do you need lookaround for the question described? if you need to print lines containing domain, use awk '/domain/{print}'.. if you do not want lines containing domain, use awk '!/domain/{print}' | |
| Oct 25, 2016 at 16:39 | comment | added | Venkat Teki | @Sundeep, missed that post..my requirement is exactly same | |
| Oct 25, 2016 at 16:34 | comment | added | Sundeep | just few minutes back this was posted - unix.stackexchange.com/questions/318839/… awk doesn't support lookarounds... | |
| Oct 25, 2016 at 16:24 | comment | added | steeldriver | Seems awk -v p="domain" '$0 !~ p' should work ... ? | |
| Oct 25, 2016 at 16:18 | history | asked | Venkat Teki | CC BY-SA 3.0 |