Timeline for Four tasks in parallel... how do I do that?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 31, 2012 at 20:30 | comment | added | jw013 | Just to explain my fixes to the code: (1) As a matter of style, avoid all uppercase variable names as they potentially conflict with internal shell variables. (2) Added quoting for $f etc. (3) Use [ for POSIX compatible scripts, but for pure bash [[ is always preferred. In this case, (( is more appropriate for the arithmetic. | |
| Mar 31, 2012 at 20:25 | history | edited | jw013 | CC BY-SA 3.0 | Made the code more idiomatic bash. |
| Mar 31, 2012 at 19:59 | comment | added | Nils | This will wait for the last of the four concurrent processes and will then start a set of another four. Perhaps one should build an array of four PIDs and then wait for these specific PIDs? | |
| Mar 31, 2012 at 5:42 | history | answered | Frederik Deweerdt | CC BY-SA 3.0 |