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lang-bash
var=3 bash -c "/bin/echo '$var'", the single quotes within the double quotes are literal, so don't prevent parameter expansion$varin the shell, wherevaris unset. So the child shell which the shell forks to execute the double quoted content sees/bin/echo ''. See Arrow's answer."/bin/echo '$var'"to/bin/echo ''(assumingvaris undefined). parameter expansion happens before quote removal.