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You could do something like:

LC_ALL=C free -h | awk ' /^Mem/ { suffix = $2 sub(/[0-9.]*/, "", suffix) printf "%.0f%sB\n", $2, suffix }' 

(LC_ALL=C to make sure the numbers are printed using the . decimal radix (3.7G would be output as 3,7G in locales using comma as the decimal radix)).

On GNU/Linux systems, you can also do:

awk '/^MemTotal/{print $2*1024}' < /proc/meminfo | numfmt --to=iec --format=%.0f --suffix=B 

Or:

free -h | awk '/^Mem/{print $2}' | numfmt --from=iec --to=iec --format=%.0f --suffix=B 

(that one coping with locales where the decimal radix is not .).

Note that free on Linux reports that MemTotal field of /proc/meminfo. As per proc(5), that's the total usable RAM (i.e., physical RAM minus a few reserved bits and the kernel binary code). For the physical RAM, and for PCs, as pointed out by @StephenKit, you may be better off using dmidecode to get the information from the BIOS, though you'd need superuser privileges for that:

sudo dmidecode -t memory | awk '  $1 == "Size:" {total += $2} END{print total * 1024}' | numfmt --to=iec --suffix=B --format=%.0f 

You could do something like:

memory=$( LC_ALL=C free -h | awk '   /^Mem/ {   suffix = $2   sub(/[0-9.]*/, "", suffix)   printf "%.0f%sB\n", $2, suffix   }' ) 

(LC_ALL=C to make sure the numbers are printed using the . decimal radix (3.7G would be output as 3,7G in locales using comma as the decimal radix)).

On GNU/Linux systems, you can also do:

memory=$( awk '/^MemTotal/{print $2*1024}' < /proc/meminfo |   numfmt --to=iec --format=%0f --suffix=B ) 

Or:

memory=$( free -h | awk '/^Mem/{print $2}' |   numfmt --from=iec --to=iec --format=%0f --suffix=B ) 

(that one coping with locales where the decimal radix is not .).

Note that free on Linux reports that MemTotal field of /proc/meminfo. As per proc(5), that's the total usable RAM (i.e., physical RAM minus a few reserved bits and the kernel binary code). For the physical RAM, and for PCs, as pointed out by @StephenKit, you may be better off using dmidecode to get the information from the BIOS, though you'd need superuser privileges for that:

physical_memory=$( sudo dmidecode -t memory |   awk '$1 == "Size:" && $2 ~ /^[0-9]+$/ {print $2$3}' | numfmt --from=iec --suffix=B |   awk '{total += $1}; END {print total}' |  numfmt --to=iec --suffix=B --format=%0f ) 

You could do something like:

LC_ALL=C free -h | awk ' /^Mem/ { suffix = $2 sub(/[0-9.]*/, "", suffix) printf "%.0f%sB\n", $2, suffix }' 

(LC_ALL=C to make sure the numbers are printed using the . decimal radix (3.7G would be output as 3,7G in locales using comma as the decimal radix)).

On GNU/Linux systems, you can also do:

awk '/^MemTotal/{print $2*1024}' < /proc/meminfo | numfmt --to=iec --format=%.0f --suffix=B 

Or:

free -h | awk '/^Mem/{print $2}' | numfmt --from=iec --to=iec --format=%.0f --suffix=B 

(that one coping with locales where the decimal radix is not .).

You could do something like:

LC_ALL=C free -h | awk ' /^Mem/ { suffix = $2 sub(/[0-9.]*/, "", suffix) printf "%.0f%sB\n", $2, suffix }' 

(LC_ALL=C to make sure the numbers are printed using the . decimal radix (3.7G would be output as 3,7G in locales using comma as the decimal radix)).

On GNU/Linux systems, you can also do:

awk '/^MemTotal/{print $2*1024}' < /proc/meminfo | numfmt --to=iec --format=%.0f --suffix=B 

Or:

free -h | awk '/^Mem/{print $2}' | numfmt --from=iec --to=iec --format=%.0f --suffix=B 

(that one coping with locales where the decimal radix is not .).

Note that free on Linux reports that MemTotal field of /proc/meminfo. As per proc(5), that's the total usable RAM (i.e., physical RAM minus a few reserved bits and the kernel binary code). For the physical RAM, and for PCs, as pointed out by @StephenKit, you may be better off using dmidecode to get the information from the BIOS, though you'd need superuser privileges for that:

sudo dmidecode -t memory | awk ' $1 == "Size:" {total += $2} END{print total * 1024}' | numfmt --to=iec --suffix=B --format=%.0f 

You could do something like:

free -h | awk ' /^Mem/ { suffix = $2 sub(/[0-9.]*/, "", suffix) printf "%.0f%sB\n", $2, suffix }' 

You could do something like:

LC_ALL=C free -h | awk ' /^Mem/ { suffix = $2 sub(/[0-9.]*/, "", suffix) printf "%.0f%sB\n", $2, suffix }' 

(LC_ALL=C to make sure the numbers are printed using the . decimal radix (3.7G would be output as 3,7G in locales using comma as the decimal radix)).

On GNU/Linux systems, you can also do:

awk '/^MemTotal/{print $2*1024}' < /proc/meminfo | numfmt --to=iec --format=%.0f --suffix=B 

Or:

free -h | awk '/^Mem/{print $2}' | numfmt --from=iec --to=iec --format=%.0f --suffix=B 

(that one coping with locales where the decimal radix is not .).