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lang-bash
$input? Also, thecasestatement is partial (not closed byesac), and you're not using$valanywhere.case "$input". It seems to me that the esac is missing. Or shall$inputbe printed only in the last case? And why$inputand not$val? Strange code...$inputin thecasestatement is good practice, but actually not necessary. unix.stackexchange.com/questions/68694/… (note, I always quote the expansion incasestatements)