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Explore Stack InternalEdit: 1st:
find -type f -exec grep -I -q . {} \; -exec sh -c 'echo -e "$(basename "$0") {}"' {} \; | sort | cut -d ' ' -f2 | xargs sed -Ee 's/(^.{3})(.*)/\1/g' I tried for 2 hours and thisgrep -I -q . {} \; will find all the best solution I got:text files only, not binary files like images,etc.`
2nd:
Edit:
I tried for 2 hours and this the best solution I got:
Edit: 1st:
find -type f -exec grep -I -q . {} \; -exec sh -c 'echo -e "$(basename "$0") {}"' {} \; | sort | cut -d ' ' -f2 | xargs sed -Ee 's/(^.{3})(.*)/\1/g' grep -I -q . {} \; will find all the text files only, not binary files like images,etc.`
2nd:
Edit:
I tried for 2 hours and this the best solution I got:
My basic idea was to make a hash function with key equals basename and it's value equals the first 3 characters.
#!/bin/bash touch file_s echo 'declare -A map' > file_s find . ! -name file_s ! -name sort_map -type f -exec grep -I -q . {} \; \ -exec sh -c 'i="$(basename "$0")";echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s;' {} \; | sort | while read -r line do source file_s echo -e ${map["$line"]} done The name of the script where you should write this code is sort_map and file_s is a temp. file. So you should not include these two files in the find command . grep -I -q . {} \; will grep files which are only text, not binary files.
The second -exec command is as follows:
i="$(basename "$0")"; will get the basename and will write into variable i.
echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s; will write hash function and it's value to temp file file_s.
sort will sort the file names.
while read -r line do source file_s echo -e ${map["$line"]} done Will read line by line and source the file file_s. Then will print the first 3 characters.
You can't use head because head prints the content of the file not the file names.
You can use:
find . -type f -exec basename {} \; | sort | cut -c 1-3 Or you can also use b option instead of c but it will assume that all the characters are of 1 byte.
find . -type f -exec basename {} \; | sort | cut -b 1-3 It will get first three characters.
You can use:
find . -type f -exec basename {} \; | sort | sed -Ee 's/(^.{3})(.*)/\1/g' It will sort the files and then will match starting three characters and will only print them.
Note: All of these commands will consider space and tab as one character.
I tried for 2 hours and this the best solution I got:
My basic idea was to make a hash function with key equals basename and it's value equals the first 3 characters.
#!/bin/bash touch file_s echo 'declare -A map' > file_s find . ! -name file_s ! -name sort_map -type f -exec grep -I -q . {} \; \ -exec sh -c 'i="$(basename "$0")";echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s;' {} \; | sort | while read -r line do source file_s echo -e ${map["$line"]} done The name of the script where you should write this code is sort_map and file_s is a temp. file. So you should not include these two files in the find command . grep -I -q . {} \; will grep files which are only text, not binary files.
The second -exec command is as follows:
i="$(basename "$0")"; will get the basename and will write into variable i.
echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s; will write hash function and it's value to temp file file_s.
sort will sort the file names.
while read -r line do source file_s echo -e ${map["$line"]} done Will read line by line and source the file file_s. Then will print the first 3 characters.
You can't use head because head prints the content of the file not the file names.
You can use:
find . -type f -exec basename {} \; | sort | cut -c 1-3 Or you can also use b option instead of c but it will assume that all the characters are of 1 byte.
find . -type f -exec basename {} \; | sort | cut -b 1-3 It will get first three characters.
You can use:
find . -type f -exec basename {} \; | sort | sed -Ee 's/(^.{3})(.*)/\1/g' It will sort the files and then will match starting three characters and will only print them.
Note: All of these commands will consider space and tab as one character.
Edit:
I tried for 2 hours and this the best solution I got:
My basic idea was to make a hash function with key equals basename and it's value equals the first 3 characters.
#!/bin/bash touch file_s echo 'declare -A map' > file_s find . ! -name file_s ! -name sort_map -type f -exec grep -I -q . {} \; \ -exec sh -c 'i="$(basename "$0")";echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s;' {} \; | sort | while read -r line do source file_s echo -e ${map["$line"]} done The name of the script where you should write this code is sort_map and file_s is a temp. file. So you should not include these two files in the find command . grep -I -q . {} \; will grep files which are only text, not binary files.
The second -exec command is as follows:
i="$(basename "$0")"; will get the basename and will write into variable i.
echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s; will write hash function and it's value to temp file file_s.
sort will sort the file names.
while read -r line do source file_s echo -e ${map["$line"]} done Will read line by line and source the file file_s. Then will print the first 3 characters.
You can't use head because head prints the content of the file not the file names.
You can use:
find . -type f -exec basename {} \; | sort | cut -c 1-3 Or you can also use b option instead of c but it will assume that all the characters are of 1 byte.
find . -type f -exec basename {} \; | sort | cut -b 1-3 It will get first three characters.
You can use:
find . -type f -exec basename {} \; | sort | sed -Ee 's/(^.{3})(.*)/\1/g' It will sort the files and then will match starting three characters and will only print them.
Note: All of these commands will consider space and tab as one character.
I tried for 2 hours and this the best solution I got:
My basic idea was to make a hash function with key equals basename and it's value equals the first 3 characters.
#!/bin/bash touch file_s echo 'declare -A map' > file_s find . ! -name file_s ! -name sort_map -type f -exec grep -I -q . {} \; \ -exec sh -c 'i="$(basename "$0")";echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s;echo "$i"'file_s;' {} \; | sort | while read -r line do source file_s echo $line echo -e ${map["$line"]} done The name of the script where you should write this code is sort_map and file_s is a temp. file. So you should not include these two files in the find command . grep -I -q . {} \; will grep files which are only text, not binary files.
The second -exec command is as follows:
i="$(basename "$0")"; will get the basename and will write into variable i.
echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s; will write hash function and it's value to temp file file_s.
sort will sort the file names.
while read -r line do source file_s echo -e ${map["$line"]} done Will read line by line and source the file file_s. Then will print the first 3 characters.
You can't use head because head prints the content of the file not the file names.
You can use:
find . -type f -exec basename {} \; | sort | cut -c 1-3 Or you can also use b option instead of c but it will assume that all the characters are of 1 byte.
find . -type f -exec basename {} \; | sort | cut -b 1-3 It will get first three characters.
You can use:
find . -type f -exec basename {} \; | sort | sed -Ee 's/(^.{3})(.*)/\1/g' It will sort the files and then will match starting three characters and will only print them.
Note: All of these commands will consider space and tab as one character.
I tried for 2 hours and this the best solution I got:
#!/bin/bash touch file_s echo 'declare -A map' > file_s find . ! -name file_s ! -name sort_map -type f -exec grep -I -q . {} \; \ -exec sh -c 'i="$(basename "$0")";echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s;echo "$i"' {} \; | sort | while read -r line do source file_s echo $line echo -e ${map["$line"]} done The name of the script where you should write this code is sort_map and file_s is a temp. file. So you should not include these two files in the find command . grep -I -q . {} \; will grep files which are only text, not binary files.
You can't use head because head prints the content of the file not the file names.
You can use:
find . -type f -exec basename {} \; | sort | cut -c 1-3 Or you can also use b option instead of c but it will assume that all the characters are of 1 byte.
find . -type f -exec basename {} \; | sort | cut -b 1-3 It will get first three characters.
You can use:
find . -type f -exec basename {} \; | sort | sed -Ee 's/(^.{3})(.*)/\1/g' It will sort the files and then will match starting three characters and will only print them.
Note: All of these commands will consider space and tab as one character.
I tried for 2 hours and this the best solution I got:
My basic idea was to make a hash function with key equals basename and it's value equals the first 3 characters.
#!/bin/bash touch file_s echo 'declare -A map' > file_s find . ! -name file_s ! -name sort_map -type f -exec grep -I -q . {} \; \ -exec sh -c 'i="$(basename "$0")";echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s;' {} \; | sort | while read -r line do source file_s echo -e ${map["$line"]} done The name of the script where you should write this code is sort_map and file_s is a temp. file. So you should not include these two files in the find command . grep -I -q . {} \; will grep files which are only text, not binary files.
The second -exec command is as follows:
i="$(basename "$0")"; will get the basename and will write into variable i.
echo "map["$i"]=$(head -n 1 "$0"|cut -c 1-3)" >> file_s; will write hash function and it's value to temp file file_s.
sort will sort the file names.
while read -r line do source file_s echo -e ${map["$line"]} done Will read line by line and source the file file_s. Then will print the first 3 characters.
You can't use head because head prints the content of the file not the file names.
You can use:
find . -type f -exec basename {} \; | sort | cut -c 1-3 Or you can also use b option instead of c but it will assume that all the characters are of 1 byte.
find . -type f -exec basename {} \; | sort | cut -b 1-3 It will get first three characters.
You can use:
find . -type f -exec basename {} \; | sort | sed -Ee 's/(^.{3})(.*)/\1/g' It will sort the files and then will match starting three characters and will only print them.
Note: All of these commands will consider space and tab as one character.