Timeline for curl and grep(?) to grab specifc string - how?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 21, 2019 at 20:06 | comment | added | Tryna Learn Somethin | @jogle900 $ curl https://example.com | grep -Po '(Welcome to websrvapp01\d+)|(webapp\s\d+)' will match "Welcome to websrvapp01" aswell as "webapp 1" and also "webapp 02" | |
| Feb 21, 2019 at 19:10 | comment | added | jogle900 | Matej - Your example worked great as well and it simpler for this specific task. I did UPvote as well. Thank you, | |
| Feb 21, 2019 at 19:10 | comment | added | jogle900 | Tryna - The second example didn't work for me. I got the following error: -bash: syntax error near unexpected token `(' These examples are still very useful and appreciated. | |
| Feb 21, 2019 at 18:57 | comment | added | jogle900 | Tryna - This is good. I am indeed trying to catch the following two letters/digits after the host name (webappsrv01/02) etc. I made a mistake though. Some of the older servers in our lab have text like this: "webapp 1" or "webapp 2". IS it possible to skip a space and the grab then grab the number? Can you show me that please? I did Upvote but I don't have enough reptuation credits for it show up. | |
| Feb 21, 2019 at 18:33 | history | edited | Tryna Learn Somethin | CC BY-SA 4.0 | added 150 characters in body; added 4 characters in body |
| Feb 21, 2019 at 18:27 | history | answered | Tryna Learn Somethin | CC BY-SA 4.0 |