Timeline for How to replace an optional suffix in sed
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 4, 2020 at 20:33 | history | edited | Whimusical | CC BY-SA 4.0 | added 126 characters in body |
| May 4, 2020 at 20:32 | vote | accept | Whimusical | ||
| May 4, 2020 at 20:25 | answer | added | Kusalananda♦ | timeline score: 1 | |
| May 4, 2020 at 19:50 | answer | added | bey0nd | timeline score: 1 | |
| May 4, 2020 at 19:47 | comment | added | bu5hman | Please don't expand in comments... others cant follow easily, so clarify your answer in the post. Do you mean you are trying to specify something like {0,1} means wrap the first argument, {0,2} means wrap the first 2, maybe {1,2} means wrap the second only? | |
| May 4, 2020 at 19:37 | comment | added | bu5hman | You mean you want to capture each repetition and treat each of them individually in the replacement depending on how many repetitions you get? You will have to define some sort of rule. | |
| May 4, 2020 at 19:26 | comment | added | Whimusical | I need to respect the capability of referring to each match in the output like in \1 - \2 - \3, so I can embellish them invidivdually. I just wrote a simplification of my need | |
| May 4, 2020 at 18:41 | answer | added | bu5hman | timeline score: 1 | |
| May 4, 2020 at 18:29 | comment | added | schrodingerscatcuriosity | sed 's/^\([^,]*\)/[\1]/' gives the output you show, but I'm not sure I completely understand you. | |
| May 4, 2020 at 18:20 | history | asked | Whimusical | CC BY-SA 4.0 |