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Jan 27 at 17:25 history edited Lesmana CC BY-SA 4.0
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Apr 20, 2022 at 7:11 history edited Lesmana CC BY-SA 4.0
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May 9, 2021 at 12:23 comment added Love Grover Is it possible to execute time-command with every command I type
Apr 29, 2021 at 13:56 history edited Lesmana CC BY-SA 4.0
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Mar 5, 2021 at 9:14 history edited Lesmana CC BY-SA 4.0
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Feb 15, 2021 at 15:51 history edited Lesmana CC BY-SA 4.0
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Sep 5, 2018 at 11:25 history edited Lesmana CC BY-SA 4.0
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Aug 15, 2018 at 7:33 history edited Lesmana CC BY-SA 4.0
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Apr 24, 2018 at 18:39 history edited Lesmana CC BY-SA 3.0
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Apr 24, 2018 at 17:42 history edited Lesmana CC BY-SA 3.0
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Apr 24, 2018 at 17:14 history edited Lesmana CC BY-SA 3.0
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Apr 24, 2018 at 17:10 comment added Lesmana i elaborated the answer. now give me upvotes. sweet sweet upvotes.
Apr 24, 2018 at 17:09 history edited Lesmana CC BY-SA 3.0
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Apr 24, 2018 at 17:01 history edited Lesmana CC BY-SA 3.0
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Apr 23, 2018 at 19:32 comment added JakeRobb I'm with @j0h -- how do you actually use this? You've shown how to invoke it, but not how to acquire the result. (Experimentally, I've determined that the result is printed to stdout if the command has no output of its own, but what if it does?) And what are the meanings of --getsomecoffee and --callmom? Does this somehow label the thing being timed? This answer needs improvement. (And yes, I'm aware two years have gone by.)
Jul 26, 2017 at 10:59 review Suggested edits
Jul 26, 2017 at 11:48
Apr 5, 2016 at 14:58 comment added j0h I dont get it, what are the comments for? what is the output of this function?
Aug 14, 2013 at 0:33 comment added sparticvs Additionally you can do time { command; command2; }
Aug 13, 2013 at 22:58 vote accept spuder
Aug 13, 2013 at 22:24 comment added Drav Sloan Note that \ is a shortcut version of the command function of bash, so command time longrunningcommand --pedantic-comments is the same :)
Aug 13, 2013 at 22:20 history answered Lesmana CC BY-SA 3.0