Get current timezone on CentOS 7?

Question

On previous version of CentOS, I used the following command to get the current timezone in my bash script:

timezone=$(sed 's/ZONE=//g' /etc/sysconfig/clock)

Output is "America/New_York"

How can I achieve an exact output on CentOS 7?

Marcin · Accepted Answer · 2015-01-14 16:56:03Z

6

CentOS 7 specific:

timedatectl | gawk -F': ' ' $1 ~ /Timezone/ {print $2}'

And displaying just the timezone:

timedatectl | gawk -F'[: ]+' ' $2 ~ /Timezone/ {print $3}'

more generic:

date +%Z

answered Jan 14, 2015 at 15:31

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cuonglm · Accepted Answer · 2015-01-14 17:12:59Z

If you don't mind using perl, you can use DateTime::TimeZone module from CPAN:

$ perl -MDateTime::TimeZone -E ' say DateTime::TimeZone->new(name => "local")->name(); ' Asia/Ho_Chi_Minh

POSIXly, you can use date with %Z format:

$ date +%Z ICT

Jeff Schaller · Accepted Answer · 2019-04-15 23:24:43Z

1

timedatectl | awk '/Time zone:/ {print $3}'

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answered Apr 15, 2019 at 23:00

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Zombo · Accepted Answer · 2018-07-01 14:05:15Z

For the time zone, you can use geolocation:

$ curl https://ipapi.co/timezone America/Chicago

Or:

$ curl http://ip-api.com/line?fields=timezone America/Chicago

This doesn't seem to jive with the original intent of the question. The locale can be set independent of where the IP of the box resides geo-wise. — slm
– slm ♦, Commented Jul 1, 2018 at 16:46

4 Answers 4