Run command 2 regardless of whether command 1 succeeds or not [duplicate]

Question

I have cmd1 and cmd2.

cmd1 && cmd2 will not run cmd2 if cmd1 fails.

cmd1 || cmd2 will run cmd2 if cmd1 fails

How do I run cmd2 regardless of whether cmd1 succeeds or not?

ash · Accepted Answer · 2024-03-01 20:20:07Z

35

To execute cmd2 regardless of whether the previous one result is, separate your command with semicolons or newlines:

cmd1; cmd2 # or cmd1 cmd2

If set -e is enabled, add || true to ignore the result of the preceding command:

set -e cmd1 || true; cmd2 # or cmd1 || true cmd2

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answered Sep 29, 2015 at 10:06

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