I have a word and I want to check what the percent of its appearance in a file ( according to the total number of word in the file ) ? For example if I have the word "you" and it appears 2 times in a file with 8 words the output will be 25%.
I tried: fgrep -ow
you can get the total numbers of words in your file as follow
nw=`wc -w < /path/to/file` And the number of occurrences of a certain word/pattern with
occurrences=`egrep -c <pattern> /path/to/file` then you can easily calculate the percentage and put the result in a variable
result=`echo "scale=2; $occurrences*100/$nw" | bc` to add the % you can eg. do as follow
echo $result'%' Use the same logic as shown URL
tr ' ' '\n' < file.txt | awk '{if($0=="her"){nmw+=1}}END{print ((nmw*100)/NR)}' 
her with string you want to search so for your case it is you. With awk:
awk -vw="word" 'BEGIN{RS="[^a-zA-Z]+"} $0==w{c++} END{printf "%.1f%%\n",c*100/NR}' file -vw="word" gives awk the variable w which contains "word". That is the word, you want to have the percentage.BEGIN{RS="[^a-zA-Z]+"} sets the row separator to everything, but letter, so every word is processed separately.$0==w{c++} increase the counter if the word is found.END{printf "%.1f%%\n",c*100/NR} print the calculated number after the file is processed