I am trying to schedule a service using systemd on Oracle Linux Server 7.7.
The use-case is simple; the timer needs to run the service in every hour (between 2PM and 9AM) - but, only if that is not running already. By this answer, I thought it is the case by default.
So, the expectation would be:
- 2:00: timer starts the service - service begins to run and let's say it runs for 90 mins this time
- 3:00: since the service is still running, do nothing this time
- 4:00: service has completed around 3:30, so start the service again - service runs for 20 mins now
- 5:00: timer starts the service again
- ...
However, the current result is:
- 2:00: timer starts the service - service begins to run and let's say it runs for 90 mins this time
- 3:00: since the service is still running, do nothing
- 3:30: the service completes, so it gets started again, immediately
- ...
Could someone help me with this?
Thanks, guys!
my timer:
[Unit] Description=Run service between 02-21 (inclusive) every hour [Timer] # the 02..21 syntax didn't work on this distribution, but I am open to suggestions to simplify it :) OnCalendar=*-*-* 02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21:00:00 Unit=test-service.service [Install] WantedBy=timers.target my service:
[Unit] Description=Service for testing purposes [Service] WorkingDirectory=/opt/apps/long-running-service ExecStart=/opt/apps/long-running-service Restart=no KillSignal=SIGINT [Install] WantedBy=multi-user.target 