How can I convert a file path to an URI in the command-line?
Example:
/home/MHC/directory with spaces and ümläuts to
file:///home/MHC/directory%20with%20spaces%20and%20%C3%BCml%C3%A4uts 
- 2stackoverflow.com/q/11876353/486504user– user2012-12-26 21:28:05 +00:00Commented Dec 26, 2012 at 21:28
- 2stackoverflow.com/q/296536/486504user– user2012-12-26 21:28:44 +00:00Commented Dec 26, 2012 at 21:28
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5 Answers
One way to do this is using urlencode (install it on Ubuntu via sudo apt-get install gridsite-clients).
urlencode -m "$filepath" will convert the path to an URI. The "file://" part of the URI will be left out, but you can easily add that via a bash one-liner:
uri=$(urlencode -m "$1"); echo "file://$uri" or directly
echo "file://$(urlencode -m "$1")" or
echo -n file://; urlencode -m "$1" Many thanks to Michael Kjörling for the references!
- Don't forget the quotes! You probably want
encodeduri=$(urlencode -m "$uri")with$uriin double quotes!gniourf_gniourf– gniourf_gniourf2012-12-26 21:49:35 +00:00Commented Dec 26, 2012 at 21:49 - @gniourf_gniourf Thank you, modified the code accordingly.Glutanimate– Glutanimate2012-12-26 21:55:05 +00:00Commented Dec 26, 2012 at 21:55
- Fails for me, transforms "é" to "%FF%FF" (on Debian Buster)Olivier Cailloux– Olivier Cailloux2020-09-07 19:44:20 +00:00Commented Sep 7, 2020 at 19:44
- Also didn't work for me, I got a bunch of
%FFfor cyrillic symbols.HolyBlackCat– HolyBlackCat2020-10-24 08:13:25 +00:00Commented Oct 24, 2020 at 8:13
On CentOS, no extra dependencies needed:
$ python -c "import urllib;print urllib.quote(raw_input())" <<< "$my_url" 
- 1With
pathlibmodule it could be done viapython -c 'import sys,pathlib; print(pathlib.Path(sys.argv[1]).resolve().as_uri())' "$my_url"umi– umi2019-06-19 18:53:55 +00:00Commented Jun 19, 2019 at 18:53 - 1
pathlibis only available in Python 3, which is not installed by default on CentOS.Rockallite– Rockallite2019-06-20 02:06:10 +00:00Commented Jun 20, 2019 at 2:06 - 1
raw_input()was renamed toinput()in Python3Mendhak– Mendhak2021-11-14 08:43:45 +00:00Commented Nov 14, 2021 at 8:43
You can also use the Perl module URI::file directly from the command line:
$ path="/home/MHC/directory with spaces and ümläuts" $ echo $path | perl -MURI::file -e 'print URI::file->new(<STDIN>)."\n"' file:///home/MHC/directory%20with%20spaces%20and%20%C3%BCml%C3%A4uts $ - 1Can be shortened to
echo $path | perl -MURI::file -E 'say URI::file->new(<>)'with Perl 5.10 (from year 2007) or newerDaniel Böhmer– Daniel Böhmer2019-04-02 22:24:45 +00:00Commented Apr 2, 2019 at 22:24
Rockallite gave a good answer, but I didn't want to type that every time.
I made a reusable bash function to do this called "file2url". To see where to save bash functions, take a look at this thread on SO.
file2url () { python -c "import sys, pathlib; print(pathlib.Path(input()).resolve().as_uri())" <<< $1 } This assumes that you have a python3 installed with the name "python".
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sysdoesn't seem to be usedKiruahxh– Kiruahxh2023-06-20 14:01:36 +00:00Commented Jun 20, 2023 at 14:01
You can pass path as argument to the following script:
#!/usr/bin/env gjs const { Gio } = imports.gi; let path = Gio.File.new_for_path(ARGV[0]); let uri = path.get_uri(); print(uri); To convert from uri to path use the following script:
#!/usr/bin/env gjs const { Gio } = imports.gi; let uri = Gio.File.new_for_uri(ARGV[0]); let path = uri.get_path(); print(path); 