Top MCQs on Bitwise Algorithms and Bit Manipulations with Answers

Which bitwise operator is used to swap two numbers?

What is the output of the below code for input num = 15?

unsigned int fun(unsigned int n) {  unsigned int count = 0;  while (n) {  count += n & 1;  n >>= 1;  }  return count; } 

unsigned int fun(unsigned int n) {  unsigned int count = 0;  while (n) {  count += n & 1;  n >>= 1;  }  return count; } 

public class Main {  public static int fun(int n) {  int count = 0;  while (n != 0) {  count += n & 1;  n >>= 1;  }  return count;  } } 

def fun(n): count = 0 while n: count += n & 1 n >>= 1 return count 

function fun(n) {  let count = 0;  while (n) {  count += n & 1;  n >>= 1;  }  return count; } 

Which is the format specifier used to prefix 0x and print a number in hexadecimal notation.?

Which is the Bit Toggling operator below.?

What is the output of the below expression? 

000111 | 01010

Bitwise & can be used in conjunction with ~ operator to turn off 1 or more bits in a number.

If we have to add two numbers without having any carry, which bitwise operator should be used?

Predict the output:

#include <iostream> using namespace std; int main() {  int x = -5;  x = x >> 1;  cout << x << endl;  return 0; } 

#include <stdio.h> int main() {  int x = -5;  x = x >> 1;  printf("%d\n", x);  return 0; } 

public class Main {  public static void main(String[] args) {  int x = -5;  x = x >> 1;  System.out.println(x);  } } 

# x is initialized to -5 x = -5 # Right shift operation x = x >> 1 # Print the result print(x) 

// x is initialized to -5 let x = -5; // Right shift operation x = x >> 1; // Print the result console.log(x); 

What is the output of the below code?

#include <bits/stdc++.h> using namespace std; int main() {  if (~0 == 1)  cout << "Yes";  else  cout << "No"; } 

#include <stdio.h> int main() {  if (~0 == 1)  printf("Yes");  else  printf("No");  return 0; } 

public class Main {  public static void main(String[] args) {  if (~0 == 1)  System.out.println("Yes");  else  System.out.println("No");  } } 

if ~0 == 1: print("Yes") else: print("No") 

if (~0 === 1)  console.log("Yes"); else  console.log("No"); 

What will the below code do?

void function(int& num, int pos)  {  num |= (1 << pos);  } 

void setBit(int* num, int pos) {  *num |= (1 << pos);  } 

void setBit(int[] num, int pos) {  num[0] |= (1 << pos);  } 

def set_bit(num, pos): return num | (1 << pos) 

function setBit(num, pos) {  return num | (1 << pos); }