Replace new line/return with space using regex in java

Replace new line/return with space using regex in java

To replace newline characters (line breaks) or carriage return characters with spaces using a regular expression in Java, you can use the String.replaceAll() method with an appropriate regular expression pattern. Here's an example:

public class ReplaceNewlineWithSpace { public static void main(String[] args) { // Input string with newline and carriage return characters String input = "Hello,\nworld!\rThis is a sample text."; // Replace newline and carriage return characters with spaces String result = input.replaceAll("[\n\r]", " "); // Print the result System.out.println(result); } }

In this example:

  • We start with an input string (input) that contains newline (\n) and carriage return (\r) characters.

  • We use the replaceAll method on the input string and provide a regular expression pattern [\\n\\r] to match both newline and carriage return characters.

  • We specify the replacement string " " (a single space) as the second argument to replaceAll.

  • The result is stored in the result variable, where newline and carriage return characters have been replaced with spaces.

  • Finally, we print the result, which will show the original text with newline and carriage return characters replaced by spaces.

The output will be:

Hello, world! This is a sample text.

The regular expression [\\n\\r] matches both newline and carriage return characters, so it effectively replaces them with spaces in the input string.

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