Find the smallest power of 2 greater than or equal to n in Python

Find the smallest power of 2 greater than or equal to n in Python

To find the smallest power of 2 greater than or equal to a given number n in Python, you can use the math.ceil() function along with the base-2 logarithm (math.log2()). Here's a Python function to do this:

import math def smallest_power_of_2(n): if n <= 0: raise ValueError("Input must be a positive integer") return 2 ** math.ceil(math.log2(n)) # Example usage: n = 10 result = smallest_power_of_2(n) print(result) # Output will be 16

In this code:

  1. We import the math module to access mathematical functions.

  2. The smallest_power_of_2() function takes an input n.

  3. We first check if n is less than or equal to 0 because the smallest power of 2 is 1, which is greater than 0.

  4. We use math.log2(n) to calculate the base-2 logarithm of n.

  5. We use math.ceil() to round up the result of math.log2(n) to the nearest integer, which ensures that we get the smallest power of 2 that is greater than or equal to n.

  6. Finally, we return 2 raised to the power of the rounded-up result, which gives us the smallest power of 2.

This function will work for positive integers n. If n is already a power of 2, it will return n itself.

Examples

  1. How to find the smallest power of 2 greater than or equal to a given number in Python?

    Description: This code snippet demonstrates how to use bitwise operations to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 n -= 1 n |= n >> 1 n |= n >> 2 n |= n >> 4 n |= n >> 8 n |= n >> 16 return n + 1 # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  2. How to find the smallest power of 2 greater than or equal to a given number using logarithms in Python?

    Description: This function utilizes logarithms to find the smallest power of 2 greater than or equal to a given number.

    import math def smallest_power_of_2(n): if n <= 0: return 1 power = math.ceil(math.log2(n)) return 2 ** power # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  3. How to find the smallest power of 2 greater than or equal to a given number using bit manipulation in Python?

    Description: This code snippet demonstrates how to use bit manipulation to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 n -= 1 n |= n >> 1 n |= n >> 2 n |= n >> 4 n |= n >> 8 n |= n >> 16 return n + 1 # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  4. How to find the smallest power of 2 greater than or equal to a given number using a loop in Python?

    Description: This function uses a loop to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 power = 1 while power < n: power <<= 1 return power # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  5. How to find the smallest power of 2 greater than or equal to a given number using binary search in Python?

    Description: This code snippet demonstrates how to use binary search to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 left, right = 0, n while left < right: mid = (left + right) // 2 if 2 ** mid < n: left = mid + 1 else: right = mid return 2 ** left # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  6. How to find the smallest power of 2 greater than or equal to a given number using recursion in Python?

    Description: This function utilizes recursion to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 if n & (n - 1) == 0: return n return smallest_power_of_2(n + 1) # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  7. How to find the smallest power of 2 greater than or equal to a given number using the math module in Python?

    Description: This code snippet demonstrates how to use the math.ceil function with logarithms to find the smallest power of 2 greater than or equal to a given number.

    import math def smallest_power_of_2(n): if n <= 0: return 1 power = math.ceil(math.log2(n)) return 2 ** power # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  8. How to find the smallest power of 2 greater than or equal to a given number using bit shifting in Python?

    Description: This function uses bit shifting to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 n -= 1 n |= n >> 1 n |= n >> 2 n |= n >> 4 n |= n >> 8 n |= n >> 16 return n + 1 # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  9. How to find the smallest power of 2 greater than or equal to a given number using a generator in Python?

    Description: This code snippet demonstrates how to use a generator to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 return next(2 ** i for i in range(n) if 2 ** i >= n) # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

  10. How to find the smallest power of 2 greater than or equal to a given number using a while loop in Python?

    Description: This function uses a while loop to find the smallest power of 2 greater than or equal to a given number.

    def smallest_power_of_2(n): if n <= 0: return 1 power = 1 while power < n: power <<= 1 return power # Example usage number = 10 smallest_power = smallest_power_of_2(number) print("Smallest power of 2 greater than or equal to", number, ":", smallest_power)

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