Read a large zipped text file line by line in python

Read a large zipped text file line by line in python

To read a large zipped text file line by line in Python, you can use the gzip module to handle the decompression of the file and then read the lines using a loop. Here's a step-by-step guide:

  1. Import the necessary module:

    You'll need the gzip module to decompress the file.

    import gzip

  2. Open the zipped file for reading:

    Open the zipped file using gzip.open(). Replace 'your_file.gz' with the actual file path.

    with gzip.open('your_file.gz', 'rt') as file: # 'rt' specifies that we want to open the file in text mode # (read as text, not binary) for line in file: # Process each line here print(line.strip()) # Example: Stripping newline characters

    This code opens the zipped file and reads it line by line. You can process each line inside the loop as needed.

Here's a complete example:

import gzip with gzip.open('your_file.gz', 'rt') as file: for line in file: # Process each line here print(line.strip()) # Example: Stripping newline characters

Replace 'your_file.gz' with the path to your zipped text file. Make sure to adapt the processing logic inside the loop to suit your specific requirements.

Examples

  1. How to read a large zipped text file line by line in Python?

    • Use the zipfile module to read a zipped text file and process it line by line.
    import zipfile with zipfile.ZipFile('large_file.zip', 'r') as zf: with zf.open('file.txt') as f: for line in f: print(line.decode().strip()) # Process each line

  2. How to read a large GZIP file line by line in Python?

    • Use the gzip module to read a large GZIP file and process it line by line.
    import gzip with gzip.open('large_file.gz', 'rt') as f: # 'rt' to read as text for line in f: print(line.strip()) # Process each line

  3. How to handle large files in memory-efficient ways in Python?

    • Use a streaming approach to read large files line by line to avoid high memory usage.
    import zipfile with zipfile.ZipFile('large_file.zip', 'r') as zf: with zf.open('file.txt') as f: for line in f: # Process each line without loading the entire file into memory print(line.decode().strip())

  4. How to read a specific file from a ZIP archive in Python?

    • Extract a specific file from a ZIP archive and process it line by line.
    import zipfile with zipfile.ZipFile('archive.zip', 'r') as zf: with zf.open('data/large_file.txt') as f: for line in f: print(line.decode().strip()) # Process each line

  5. How to read a large zipped CSV file line by line in Python?

    • Use the csv module with zipfile to read a large zipped CSV file line by line.
    import zipfile import csv with zipfile.ZipFile('large_csv_file.zip', 'r') as zf: with zf.open('data.csv') as f: csv_reader = csv.reader(f) for row in csv_reader: print(row) # Process each row of the CSV

  6. How to read a large text file from a ZIP archive with UTF-8 encoding?

    • Explicitly specify UTF-8 encoding when reading text files from a ZIP archive.
    import zipfile with zipfile.ZipFile('large_text_file.zip', 'r') as zf: with zf.open('file.txt') as f: for line in f: print(line.decode('utf-8').strip()) # Process with UTF-8 encoding

  7. How to handle exceptions when reading a zipped file in Python?

    • Use exception handling to manage potential errors when reading from a ZIP archive.
    import zipfile try: with zipfile.ZipFile('large_file.zip', 'r') as zf: with zf.open('file.txt') as f: for line in f: print(line.decode().strip()) # Process each line except zipfile.BadZipFile: print("Error: Bad ZIP file") except FileNotFoundError: print("Error: File not found in ZIP archive")

  8. How to read multiple files from a ZIP archive in Python?

    • Read multiple files from a ZIP archive and process them line by line.
    import zipfile with zipfile.ZipFile('archive.zip', 'r') as zf: for file_name in zf.namelist(): # List all files in the archive with zf.open(file_name) as f: print(f"Reading {file_name}:") for line in f: print(line.decode().strip())

  9. How to extract and read a large zipped text file in Python?

    • Extract a specific file from a ZIP archive to a temporary location, then read it line by line.
    import tempfile 
    import zipfile import tempfile with zipfile.ZipFile('archive.zip', 'r') as zf: with tempfile.TemporaryDirectory() as temp_dir: zf.extract('file.txt', path=temp_dir) # Extract the file to a temp location with open(f'{temp_dir}/file.txt', 'r') as f: for line in f: print(line.strip()) # Process each line

More Tags

selectionchanged command kafka-python heroku arrays html-renderer aabb ivr laravel-socialite object

More Python Questions

More Chemistry Calculators

More Biochemistry Calculators

More Weather Calculators

More Electronics Circuits Calculators