Reorder dictionary in python according to a list of values

Reorder dictionary in python according to a list of values

To reorder a Python dictionary according to a specific list of values, you can create a new dictionary that iterates over the list of values and retrieves the corresponding key-value pairs from the original dictionary. Here's a step-by-step approach to achieve this:

# Original dictionary original_dict = {'apple': 3, 'banana': 2, 'cherry': 1, 'date': 4} # List specifying the desired order of keys desired_order = ['banana', 'date', 'apple', 'cherry'] # Create a new dictionary with keys reordered according to the desired order ordered_dict = {key: original_dict[key] for key in desired_order} print(ordered_dict)

In this example, desired_order is the list specifying the desired order of keys. We iterate through this list and use the keys to retrieve the corresponding values from the original dictionary, creating a new dictionary with the desired order of keys.

The ordered_dict will now contain the key-value pairs reordered according to the list desired_order.

Examples

  1. How to reorder a Python dictionary based on a list of keys?

    • This query shows how to reorder a dictionary by matching its keys to a given list of keys.
    # Dictionary to reorder my_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4} # List of keys to reorder by key_order = ['c', 'b', 'a', 'd'] # Reordering dictionary reordered_dict = {k: my_dict[k] for k in key_order} print(reordered_dict) # Output: {'c': 3, 'b': 2, 'a': 1, 'd': 4}

  2. How to reorder a Python dictionary based on a custom sorting function?

    • This query discusses reordering a dictionary using a custom sorting function applied to the keys.
    # Dictionary to reorder my_dict = {'apple': 1, 'banana': 2, 'cherry': 3, 'date': 4} # Custom sorting function (by key length) reordered_keys = sorted(my_dict, key=lambda k: len(k)) reordered_dict = {k: my_dict[k] for k in reordered_keys} print(reordered_dict) # Output: {'date': 4, 'apple': 1, 'banana': 2, 'cherry': 3}

  3. How to reorder a Python dictionary based on values?

    • This query shows how to reorder a dictionary by its values.
    # Dictionary to reorder my_dict = {'a': 3, 'b': 1, 'c': 4, 'd': 2} # Reordering based on values reordered_dict = dict(sorted(my_dict.items(), key=lambda item: item[1])) print(reordered_dict) # Output: {'b': 1, 'd': 2, 'a': 3, 'c': 4}

  4. How to reorder a nested dictionary based on a list of outer keys in Python?

    • This query explores reordering a nested dictionary's outer level based on a specific list of keys.
    # Nested dictionary to reorder nested_dict = { 'z': {'name': 'Zack'}, 'y': {'name': 'Yara'}, 'x': {'name': 'Xander'}, } # Order of outer keys key_order = ['x', 'y', 'z'] # Reordering the outer dictionary reordered_dict = {k: nested_dict[k] for k in key_order} print(reordered_dict) # Output: {'x': {'name': 'Xander'}, 'y': {'name': 'Yara'}, 'z': {'name': 'Zack'}}

  5. How to reorder a dictionary based on keys that match a specific pattern in Python?

    • This query describes reordering a dictionary where the key order is based on a matching pattern.
    import re # Dictionary to reorder my_dict = {'123a': 1, '234b': 2, '345c': 3, '456d': 4} # Pattern to match pattern = re.compile(r'\d+[a-z]') # Reordering based on pattern match reordered_keys = sorted(my_dict, key=lambda k: pattern.search(k).group(0)) reordered_dict = {k: my_dict[k] for k in reordered_keys} print(reordered_dict) # Output: {'123a': 1, '234b': 2, '345c': 3, '456d': 4}

  6. How to reorder a dictionary and add missing keys based on a given list in Python?

    • This query shows how to reorder a dictionary and ensure missing keys are added with a default value.
    # Dictionary to reorder my_dict = {'a': 1, 'b': 2} # Desired key order with some missing keys key_order = ['c', 'a', 'b', 'd'] # Reordering and adding missing keys reordered_dict = {k: my_dict.get(k, 'default') for k in key_order} print(reordered_dict) # Output: {'c': 'default', 'a': 1, 'b': 2, 'd': 'default'}

  7. How to reorder a dictionary based on multiple attributes (keys and values) in Python?

    • This query shows how to reorder a dictionary based on a combination of keys and values.
    # Dictionary to reorder my_dict = {'a': 3, 'b': 1, 'c': 4, 'd': 2} # Reordering by both key and value reordered_dict = dict(sorted(my_dict.items(), key=lambda item: (item[1], item[0]))) print(reordered_dict) # Output: {'b': 1, 'd': 2, 'a': 3, 'c': 4}

  8. How to reorder a Python dictionary based on a predefined order and other keys later?

    • This query demonstrates reordering a dictionary, first by a predefined order and then appending remaining keys.
    # Dictionary to reorder my_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4} # Predefined order key_order = ['c', 'b'] # Reordering with predefined order followed by other keys reordered_dict = {k: my_dict[k] for k in key_order} other_keys = [k for k in my_dict if k not in key_order] for k in other_keys: reordered_dict[k] = my_dict[k] print(reordered_dict) # Output: {'c': 3, 'b': 2, 'a': 1, 'd': 4}

  9. How to reorder a dictionary based on an index list in Python?

    • This query explores reordering a dictionary where the index list indicates the order of keys.
    # Dictionary to reorder my_dict = {'a': 10, 'b': 20, 'c': 30, 'd': 40} # Index order for reordering index_order = [2, 0, 3, 1] # Reordering dictionary based on index order keys = list(my_dict.keys()) reordered_dict = {keys[i]: my_dict[keys[i]] for i in index_order} print(reordered_dict) # Output: {'c': 30, 'a': 10, 'd': 40, 'b': 20}

  10. How to reorder a dictionary by reversing its current order in Python?

    • This query discusses reordering a dictionary by reversing its current order.
    # Dictionary to reorder my_dict = {'a': 10, 'b': 20, 'c': 30, 'd': 40} # Reordering by reversing the current order reordered_dict = {k: my_dict[k] for k in reversed(my_dict)} print(reordered_dict) # Output: {'d': 40, 'c': 30, 'b': 20, 'a': 10}

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