c++ - Countdown until matching digits

C++ - Countdown until matching digits

If you're looking to implement a countdown in C++ until a certain pattern of digits appears, you can use a loop to check the condition at each iteration. Here's an example that counts down until the last two digits are both '7':

#include <iostream> #include <chrono> #include <thread> bool hasMatchingDigits(int number) { // Extract the last two digits int lastDigit = number % 10; int secondLastDigit = (number / 10) % 10; // Check if both digits are '7' return (lastDigit == 7) && (secondLastDigit == 7); } int main() { int countdown = 100; // Start countdown from 100 while (countdown > 0) { // Display the current countdown value std::cout << "Countdown: " << countdown << std::endl; // Check if the condition is met if (hasMatchingDigits(countdown)) { std::cout << "Matching digits found!" << std::endl; break; // Exit the loop when the condition is met } // Decrement the countdown value --countdown; // Sleep for a short duration (optional) std::this_thread::sleep_for(std::chrono::milliseconds(500)); } return 0; }

In this example:

  • The hasMatchingDigits function checks if the last two digits of a number are both '7'.
  • The main loop counts down from 100 and checks the condition at each step.
  • If the condition is met, the loop exits, indicating that the matching digits were found.

Examples

  1. "C++ countdown until matching digits in number"

    int number = 123456789; int countdown = 0; while (number % 10 != (number / 10) % 10) { number--; countdown++; }
    • Counts down from a given number until the last two digits match.

  2. "C++ countdown until all digits are the same"

    int number = 987654321; int countdown = 0; while (number % 10 != (number / 10) % 10 || number % 10 != (number / 100) % 10) { number--; countdown++; }
    • Counts down from a given number until all three digits are the same.

  3. "C++ countdown until specific digit pattern"

    int number = 987654321; int countdown = 0; while (number % 1000 != 321) { number--; countdown++; }
    • Counts down from a given number until a specific digit pattern is matched.

  4. "C++ countdown until palindrome number"

    int number = 999; int countdown = 0; while (number != 0 && number != reverseNumber(number)) { number--; countdown++; } int reverseNumber(int num) { int reversed = 0; while (num > 0) { reversed = reversed * 10 + num % 10; num /= 10; } return reversed; }
    • Counts down from a given number until it becomes a palindrome.

  5. "C++ countdown until sum of digits is a specific value"

    int number = 987; int countdown = 0; while (sumOfDigits(number) != 10) { number--; countdown++; } int sumOfDigits(int num) { int sum = 0; while (num > 0) { sum += num % 10; num /= 10; } return sum; }
    • Counts down from a given number until the sum of its digits is a specific value.

  6. "C++ countdown until repeating digits"

    int number = 987654321; int countdown = 0; while (!hasRepeatingDigits(number)) { number--; countdown++; } bool hasRepeatingDigits(int num) { std::vector<bool> digitSeen(10, false); while (num > 0) { int digit = num % 10; if (digitSeen[digit]) { return true; } digitSeen[digit] = true; num /= 10; } return false; }
    • Counts down from a given number until it has repeating digits.

  7. "C++ countdown until ascending order digits"

    int number = 987654321; int countdown = 0; while (!isAscendingOrder(number)) { number--; countdown++; } bool isAscendingOrder(int num) { int prevDigit = num % 10; while (num > 0) { int digit = num % 10; if (digit > prevDigit) { return false; } prevDigit = digit; num /= 10; } return true; }
    • Counts down from a given number until its digits are in ascending order.

  8. "C++ countdown until prime number"

    int number = 999; int countdown = 0; while (!isPrime(number)) { number--; countdown++; } bool isPrime(int num) { if (num <= 1) { return false; } for (int i = 2; i * i <= num; i++) { if (num % i == 0) { return false; } } return true; }
    • Counts down from a given number until it becomes a prime number.

  9. "C++ countdown until even number"

    int number = 987; int countdown = 0; while (number % 2 != 0) { number--; countdown++; }
    • Counts down from a given number until it becomes an even number.

  10. "C++ countdown until specific digit is repeated"

    int number = 987654321; int countdown = 0; while (!hasRepeatedDigit(number, 5)) { number--; countdown++; } bool hasRepeatedDigit(int num, int targetDigit) { while (num > 0) { if (num % 10 == targetDigit) { return true; } num /= 10; } return false; }
    • Counts down from a given number until a specific digit is repeated.

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