If you want to find the intersection of two arrays using the filter() function and a lambda expression, you can do it like this:
Assume you have two lists arr1 and arr2. You can filter arr1 to keep only those elements that are also present in arr2.
Here's how you can do it:
arr1 = [1, 2, 3, 4, 5] arr2 = [4, 5, 6, 7, 8] intersection = list(filter(lambda x: x in arr2, arr1)) print(intersection) # [4, 5]
In this example:
filter() function iterates through each element in arr1.lambda function returns True if the element is in arr2, and False otherwise.filter() retains the elements for which the lambda function returns True.While this method works, note that using x in arr2 for each element in arr1 can be computationally expensive for large arrays since it results in a nested loop kind of behavior. A more efficient approach for large arrays/lists would be to use sets:
intersection_set = set(arr1) & set(arr2) intersection = list(intersection_set) print(intersection)
This method takes advantage of the constant-time membership checks of sets.
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