Python - Append according to Kth character

Python - Append according to Kth character

In this tutorial, we'll explore how to append strings from one list to another list based on the kth character of each string.

Problem:

Given a list of strings str_list and an integer k (0 �� k < length of any string in str_list), append each string to one of n new lists based on its kth character.

Example:

Input: str_list = ["apple", "banana", "cherry", "dates"], k = 1

Expected Output:

{ 'p': ['apple'], 'a': ['banana', 'dates'], 'h': ['cherry'] }

Solution:

Using a Dictionary:

We can use a dictionary to categorize strings based on their kth character.

def categorize_by_kth_char(str_list, k): # Initialize an empty dictionary result_dict = {} # Iterate through each string in the list for s in str_list: # Get the kth character from the string char = s[k] # Append the string to the appropriate list in the dictionary if char not in result_dict: result_dict[char] = [] result_dict[char].append(s) return result_dict str_list = ["apple", "banana", "cherry", "dates"] k = 1 print(categorize_by_kth_char(str_list, k))

Output:

{ 'p': ['apple'], 'a': ['banana', 'dates'], 'h': ['cherry'] }

Explanation:

  1. We first initialize an empty dictionary result_dict.
  2. For each string s in str_list, we identify its kth character.
  3. We check if this character is already a key in result_dict.
    • If not, we create a new list for this key.
    • We then append the string s to the list associated with this key.

Notes:

  • This solution assumes that k is valid for all strings in str_list.
  • The function categorizes strings based on their kth character and can handle any number of strings or characters.

By following this method, we can efficiently group strings based on any specific character position.

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