Python | Append Odd element twice

Python | Append Odd element twice

In this tutorial, we'll learn how to append odd elements in a list twice.

Problem:

Given a list, duplicate the odd elements and append them to the end of the list.

Solution:

Using Loops:

  1. Iterate through the list.
  2. For each odd element, append it to the end of the list.

Here's how we can implement this:

def append_odd_twice(lst): for item in lst[:]: # Copy the list for iteration, so it doesn't lead to an infinite loop if item % 2 != 0: lst.append(item) return lst lst = [1, 2, 3, 4, 5] result = append_odd_twice(lst) print(result) # Output: [1, 2, 3, 4, 5, 1, 3, 5]

Using List Comprehension:

This method offers a more concise way to achieve the same goal:

def append_odd_twice(lst): return lst + [x for x in lst if x % 2 != 0] lst = [1, 2, 3, 4, 5] result = append_odd_twice(lst) print(result) # Output: [1, 2, 3, 4, 5, 1, 3, 5]

Notes:

  • This approach ensures that the original order of the elements in the list is maintained.
  • If you have a large list and performance is a concern, the loop method can be more efficient since it modifies the original list in-place rather than creating a new list.

This tutorial provided methods to append each odd element in a list twice in Python. Depending on your specific use case and personal preferences, you can choose the method that best fits your needs.

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