Python Counter to find the size of largest subset of anagram words

Python Counter to find the size of largest subset of anagram words

The collections.Counter class in Python is a convenient tool for counting hashable objects. It's a subclass of dict that's designed to count objects, where elements are stored as dictionary keys and their counts are stored as dictionary values.

When finding the size of the largest subset of anagram words, we need to count the words that are anagrams of each other. Since anagrams are words that have the same characters but in different orders, we can use the sorted form of each word as a key in our counter.

Here's how you could do it in Python:

from collections import Counter def largest_anagram_subset_size(words): # Count the words that are anagrams of each other by their sorted tuple of characters counts = Counter(tuple(sorted(word)) for word in words) # Find the largest count of anagrams largest_count = max(counts.values(), default=0) return largest_count # Example usage: words = ["tap", "apt", "pat", "hello", "world", "dolor", "lord"] print(largest_anagram_subset_size(words)) # Output should be 3 for 'tap', 'apt', 'pat'

In this code:

  1. We define a function largest_anagram_subset_size that takes a list of words.
  2. Inside the function, we create a Counter object that holds counts of sorted tuples of characters from each word. This sorting ensures that all anagrams map to the same key.
  3. We use the max function to find the largest count in the Counter object.
  4. We return this count, which represents the size of the largest subset of anagram words.

Note that max(counts.values(), default=0) will return 0 if the counts object is empty (if words list is empty).

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