Let's break down the problem:
Given a list of numbers and a number K, you want to compute the cumulative sum of elements at every Kth position.
For example, given the list [1, 2, 3, 4, 5, 6, 7] and K = 3, the result should be the sum of every 3 elements: [6, 15, 22]. Here's the breakdown:
1 + 2 + 3 = 64 + 5 + 6 = 157 = 7 So, the cumulative sum would be 6, 6+15, 6+15+7 which results in 6, 21, 28.Loop through the List:
Calculate Sum:
Handle Remaining Elements:
def group_sum_k(nums, k): # Calculate the number of groups groups = len(nums) // k + (1 if len(nums) % k else 0) # Compute the sum for each group sums = [sum(nums[i*k : (i+1)*k]) for i in range(groups)] # Calculate the cumulative sum for i in range(1, len(sums)): sums[i] += sums[i-1] return sums # Test numbers = [1, 2, 3, 4, 5, 6, 7] k = 3 result = group_sum_k(numbers, k) print(f"Cumulative sum at every {k}th position: {result}") When you run the program with the provided test list and k=3, you should get:
Cumulative sum at every 3th position: [6, 21, 28]
group_sum_k function first determines the number of groups using integer division and the modulo operator.This method provides an efficient way to compute the group sum till each K in a list.
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