Python Slicing | Reverse an array in groups of given size

Python Slicing | Reverse an array in groups of given size

In this tutorial, we'll learn how to reverse segments of an array based on a given group size.

Scenario:

Given an array arr = [1, 2, 3, 4, 5, 6] and a group size k = 3, we want to reverse the array in groups of size k. For the above example, the result will be [3, 2, 1, 6, 5, 4].

Steps:

  1. Iterate over the list with a step size of k.
  2. For each segment, reverse the sublist and extend the result list with this reversed sublist.
  3. Return the resultant list.

Code:

Let's implement the above steps:

def reverse_in_groups(arr, k): result = [] # Iterate over the list with step size of k for i in range(0, len(arr), k): # Reverse the sublist and extend the result list with this reversed sublist result.extend(arr[i:i+k][::-1]) return result # Test arr = [1, 2, 3, 4, 5, 6] k = 3 print(reverse_in_groups(arr, k)) # Output: [3, 2, 1, 6, 5, 4]

Additional Information:

If the length of the array is not a multiple of k, the last group may contain fewer than k elements. In such cases, the above code will still work, reversing the entire last group, even if it's smaller than k.

Summary:

In this tutorial, we learned how to reverse an array in groups of a given size. We achieved this by iterating over the list in steps of k, reversing each segment, and appending the reversed segment to the resultant list.

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