Python Program to Check whether all the rotations of a given number is greater than or equal to the given number or not

Python Program to Check whether all the rotations of a given number is greater than or equal to the given number or not

To solve this problem, we'll follow these steps:

  1. Convert the number to a string to handle its rotations easily.
  2. Create all possible rotations of this number.
  3. For each rotation, check if it's greater than or equal to the given number.
  4. If all rotations satisfy this condition, return True. Otherwise, return False.

Let's implement the solution:

def are_all_rotations_greater_or_equal(n): # Convert the number to a string num_str = str(n) # Loop through all possible rotations for i in range(len(num_str)): # Create the rotation by slicing and concatenating the string rotated = num_str[i:] + num_str[:i] # If the rotated number (as an integer) is smaller than the original, return False if int(rotated) < n: return False # If all rotations are greater than or equal to the original number, return True return True # Example usage n = 123 print(are_all_rotations_greater_or_equal(n)) # False, because 231 (rotation of 123) is greater than 123, but 312 is not. n = 111 print(are_all_rotations_greater_or_equal(n)) # True, all rotations (111, 111, 111) are equal to 111.

The function will return False for the number 123 because while one rotation (231) is greater than 123, another rotation (312) is not. For the number 111, all of its rotations are equal to 111, so the function returns True.

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