Set selected item of spinner programmatically

Question

I am working on an android project and I am using a spinner which uses an array adapter which is populated from the database.

I can't find out how I can set the selected item programmatically from the list. For example if, in the spinner I have the following items:

Category 1
Category 2
Category 3

How would I programmatically make Category 2 the selected item when the screen is created. I was thinking it might be similar to c# I.E Spinner.SelectedText = "Category 2" but there doesn't seem to be any method similar to this for Android.

Please follow this link : [How to set selection on spinner item][1] [1]: stackoverflow.com/questions/16358563/… — Maddy Sharma
– Maddy Sharma, Commented May 21, 2014 at 7:18
You can pass your index into spinner.setSelection(). That would work just fine. You can also create a method that can help you match your indexes to their actual strings. — Taslim Oseni
– Taslim Oseni, Commented May 3, 2019 at 11:05

Arun George · Accepted Answer · 2012-06-17 15:41:29Z

896

Use the following: spinnerObject.setSelection(INDEX_OF_CATEGORY2).

answered Jun 17, 2012 at 15:41

Arun George

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4 Comments

Boardy Over a year ago

Thanks, this worked great, while I was doing this I also found a way of getting the index without needing to loop through the adapter. I used the following mySpinner.setSelection(arrayAdapter.getPosition("Category 2"));

Kalel Wade Over a year ago

in case you dont have the adapter to reference. mySpinner.setSelection(((ArrayAdapter)mySpinner.getAdapter()).getPosition("Value"));

Goofyahead Over a year ago

sexSpinner.setSelection(adapter.getPosition(mUser.getGender()) == -1 ? 0 : adapter.getPosition(mUser.getGender()));

Don Larynx Over a year ago

This doesn't work if the Spinner has an onItemSelectedListener(). The Listener won't be called.

ישו אוהב אותך · Accepted Answer · 2018-02-26 04:30:39Z

100

No one of these answers gave me the solution, only worked with this:

mySpinner.post(new Runnable() { @Override public void run() { mySpinner.setSelection(position); } });

edited Feb 26, 2018 at 4:30

ישו אוהב אותך

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answered Feb 23, 2014 at 18:08

Marco Hernaiz

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1 Comment

Christ Over a year ago

I call SetSelection() just after setAdapter(). This display the 1st item always (Android 2.3), even the good one is selected in the dropView. Your solution did it for me.

John Slegers · Accepted Answer · 2016-01-24 22:13:03Z

46

public static void selectSpinnerItemByValue(Spinner spnr, long value) { SimpleCursorAdapter adapter = (SimpleCursorAdapter) spnr.getAdapter(); for (int position = 0; position < adapter.getCount(); position++) { if(adapter.getItemId(position) == value) { spnr.setSelection(position); return; } } }

You can use the above like:

selectSpinnerItemByValue(spinnerObject, desiredValue);

& of course you can also select by index directly like

spinnerObject.setSelection(index);

edited Jan 24, 2016 at 22:13

John Slegers

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answered Jun 17, 2012 at 15:44

Yaqub Ahmad

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4 Comments

Arun George Over a year ago

An error with this code is that @Boardy want the selection of Category 2 which I suppose is a String (assuming he tried using Spinner.SelectedText = "Category 2") but the above code is for a long.

Yaqub Ahmad Over a year ago

He is populating the categories from the database there must be an ID for each category.

Greg Ennis Over a year ago

Why assume it is a CursorAdapter? SpinnerAdapter works just as well.

Vadim Kotov Over a year ago

I think you have a mistake here, it should be adapter.getItem(position), not adapter.getItemId(position).

Community · Accepted Answer · 2017-05-23 11:54:59Z

Some explanation (at least for Fragments - never tried with pure Activity). Hope it helps someone to understand Android better.

Most popular answer by Arun George is correct but don't work in some cases.
The answer by Marco HC uses Runnable wich is a last resort due to additional CPU load.

The answer is - you should simply choose correct place to call to setSelection(), for example it works for me:

@Override public void onResume() { super.onResume(); yourSpinner.setSelection(pos); }

But it won't work in onCreateView(). I suspect that is the reason for the interest to this topic.

The secret is that with Android you can't do anything you want in any method - oops:( - components may just not be ready. As another example - you can't scroll ScrollView neither in onCreateView() nor in onResume() (see the answer here)

John Slegers · Accepted Answer · 2016-01-24 22:13:13Z

To find a value and select it:

private void selectValue(Spinner spinner, Object value) { for (int i = 0; i < spinner.getCount(); i++) { if (spinner.getItemAtPosition(i).equals(value)) { spinner.setSelection(i); break; } } }

David Bohunek · Accepted Answer · 2014-08-08 14:30:19Z

Why don't you use your values from the DB and store them on an ArrayList and then just use:

yourSpinner.setSelection(yourArrayList.indexOf("Category 1"));

Vadim Kotov · Accepted Answer · 2019-08-01 13:46:12Z

The optimal solution is:

 public String[] items= new String[]{"item1","item2","item3"}; // here you can use array or list ArrayAdapter adapter= new ArrayAdapter(Your_Context, R.layout.support_simple_spinner_dropdown_item, items); final Spinner itemsSpinner= (Spinner) findViewById(R.id.itemSpinner); itemsSpinner.setAdapter(adapter);

To get the position of the item automatically add the following statement

itemsSpinner.setSelection(itemsSpinner.getPosition("item2"));

For getPosition() use adpater like spinnerAdapter.getPosition(). It will resolve your problem. @PedroJoaquín

John Slegers · Accepted Answer · 2016-01-24 22:13:27Z

You can make a generic method for this kind of work as I do in my UtilityClass which is

public void SetSpinnerSelection(Spinner spinner,String[] array,String text) { for(int i=0;i<array.length;i++) { if(array[i].equals(text)) { spinner.setSelection(i); } } }

Vadim Kotov · Accepted Answer · 2019-08-01 13:46:26Z

You can easily set like this: spinner.setSelection(1), instead of 1, you can set any position of list you would like to show.

אריאל עדן · Accepted Answer · 2021-11-21 19:23:00Z

6

In Kotlin I found a simple solution using a lambda:

spinnerObjec.post {spinnerObjec.setSelection(yourIndex)}

answered Nov 21, 2021 at 19:23

אריאל עדן

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1 Comment

Jeremy Caney Over a year ago

There are twenty-four existing answers to this question, including an accepted answer with 843 (!!!) upvotes. Are you sure your answer hasn't already been provided? If not, why might someone prefer your approach over the existing approaches proposed? Are you taking advantage of new capabilities? Are there scenarios where your approach is better suited?

pazfernando · Accepted Answer · 2013-06-25 19:18:05Z

I have a SimpleCursorAdapter so I have to duplicate the data for use the respose in this post. So, I recommend you try this way:

for (int i = 0; i < spinnerRegion.getAdapter().getCount(); i++) { if (spinnerRegion.getItemIdAtPosition(i) == Integer .valueOf(signal.getInt(signal .getColumnIndexOrThrow("id_region")))) { spinnerRegion.setSelection(i); break; } }

I think that is a real way

Donny Rozendal · Accepted Answer · 2019-03-25 13:51:40Z

4

This is what I use in Kotlin:

spinner.setSelection(resources.getStringArray(R.array.choices).indexOf("Choice 1"))

answered Mar 25, 2019 at 13:51

Donny Rozendal

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1 Comment

lasec0203 Over a year ago

if indexOf can not make a match, then it returns -1, which appears to result in the default value being the selected by spinner.setSelection. I'm ok with that.

Dante · Accepted Answer · 2016-03-22 22:00:51Z

I know that is already answered, but simple code to select one item, very simple:

spGenre.setSelection( ( (ArrayAdapter) spGenre.getAdapter()).getPosition(client.getGenre()) );

Arpit Patel · Accepted Answer · 2016-07-21 10:01:07Z

3

This is work for me.

 spinner.setSelection(spinner_adapter.getPosition(selected_value)+1);

answered Jul 21, 2016 at 10:01

Arpit Patel

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1 Comment

Arpit Patel Over a year ago

Because it’s start from 0 so we have to add one for getting right answer

score 3 · Accepted Answer · 2018-07-18 15:56:34Z

This is stated in comments elsewhere on this page but thought it useful to pull it out into an answer:

When using an adapter, I've found that the spinnerObject.setSelection(INDEX_OF_CATEGORY2) needs to occur after the setAdapter call; otherwise, the first item is always the initial selection.

// spinner setup... spinnerObject.setAdapter(myAdapter); spinnerObject.setSelection(INDEX_OF_CATEGORY2);

This is confirmed by reviewing the AbsSpinner code for setAdapter.

Of course, you can select an item only after the adapter has been filled.

Anas Nadeem · Accepted Answer · 2021-09-22 10:20:21Z

This Worked For me:

mySpinner.post(new Runnable() { @Override public void run() { mySpinner.setSelection(position); spinnerAdapter.notifyDataSetChanged(); } });

Maddy Sharma · Accepted Answer · 2014-07-30 15:10:26Z

If you have a list of contacts the you can go for this:

((Spinner) view.findViewById(R.id.mobile)).setSelection(spinnerContactPersonDesignationAdapter.getPosition(schoolContact.get(i).getCONT_DESIGNATION()));

Julio Cezar Riffel · Accepted Answer · 2016-04-28 17:01:07Z

 for (int x = 0; x < spRaca.getAdapter().getCount(); x++) { if (spRaca.getItemIdAtPosition(x) == reprodutor.getId()) { spRaca.setSelection(x); break; } }

Zeeshan · Accepted Answer · 2019-02-21 00:16:43Z

Most of the time spinner.setSelection(i); //i is 0 to (size-1) of adapter's size doesn't work. If you just call spinner.setSelection(i);

It depends on your logic.

If view is fully loaded and you want to call it from interface I suggest you to call

spinner.setAdapter(spinner_no_of_hospitals.getAdapter()); spinner.setSelection(i); // i is 0 or within adapter size

Or if you want to change between activity/fragment lifecycle, call like this

spinner.post(new Runnable() { @Override public void run() { spinner.setSelection(i); } });

Mohammad Ashraful Kabir · Accepted Answer · 2020-10-12 17:06:14Z

Here is the Kotlin extension I am using:

fun Spinner.setItem(list: Array<CharSequence>, value: String) { val index = list.indexOf(value) this.post { this.setSelection(index) } }

Usage:

spinnerPressure.setItem(resources.getTextArray(R.array.array_pressure), pressureUnit)

Akshay Khajuria · Accepted Answer · 2021-09-22 11:17:31Z

Yes, you can achieve this by passing the index of the desired spinner item in the setSelection function of spinner. For example:

spinnerObject.setSelection(INDEX_OF_CATEGORY).

Juan Pablo · Accepted Answer · 2016-11-22 16:23:05Z

In my case, this code saved my day:

public static void selectSpinnerItemByValue(Spinner spnr, long value) { SpinnerAdapter adapter = spnr.getAdapter(); for (int position = 0; position < adapter.getCount(); position++) { if(adapter.getItemId(position) == value) { spnr.setSelection(position); return; } } }

You don't need to do this. adapter has a getPosition(item) call that returns int position.

Sagar Chapagain · Accepted Answer · 2019-07-04 14:10:39Z

I had made some extension function of Spinner for loading data and tracking item selection.

Spinner.kt

fun <T> Spinner.load(context: Context, items: List<T>, item: T? = null) { adapter = ArrayAdapter(context, android.R.layout.simple_spinner_item, items).apply { setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item) } if (item != null && items.isNotEmpty()) setSelection(items.indexOf(item)) } inline fun Spinner.onItemSelected( crossinline itemSelected: ( parent: AdapterView<*>, view: View, position: Int, id: Long ) -> Unit ) { onItemSelectedListener = object : AdapterView.OnItemSelectedListener { override fun onNothingSelected(parent: AdapterView<*>?) { } override fun onItemSelected(parent: AdapterView<*>, view: View, position: Int, id: Long) { itemSelected.invoke(parent, view, position, id) } } }

Usaage Example

val list = listOf("String 1", "String 2", "String 3") val defaultData = "String 2" // load data to spinner your_spinner.load(context, list, defaultData) // load data without default selection, it points to first item your_spinner.load(context, list) // for watching item selection your_spinner.onItemSelected { parent, view, position, id -> // do on item selection }

JosinMC · Accepted Answer · 2017-08-31 17:08:28Z

This worked for me:

@Override protected void onStart() { super.onStart(); mySpinner.setSelection(position); }

It's similar to @sberezin's solution but calling setSelection() in onStart().

Vikhyat Chandra · Accepted Answer · 2019-05-29 09:23:20Z

I had the same issue since yesterday.Unfortunately the first item in the array list is shown by default in spinner widget.A turnaround would be to find the previous selected item with each element in the array list and swap its position with the first element.Here is the code.

OnResume() { int before_index = ShowLastSelectedElement(); if (isFound){ Collections.swap(yourArrayList,before_index,0); } adapter = new ArrayAdapter<String>(CurrentActivity.this, android.R.layout.simple_spinner_item, yourArrayList); adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item; yourListView.setAdapter(adapter); } ... private int ShowLastSelectedElement() { String strName = ""; int swap_index = 0; for (int i=0;i<societies.size();i++){ strName = yourArrayList.get(i); if (strName.trim().toLowerCase().equals(lastselectedelement.trim().toLowerCase())){ swap_index = i; isFound = true; } } return swap_index; }

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