I would like to compare strings but the following code won't work. I'm guessing it's because incompatible, is there any other way to do it?Thanks!
public class test { public static void main(String[] args) { String str1 = "abc def ghi abc ded abc ghi"; String str2 = "ghi"; int count = 0; String array[] = str1.split("\t"); for(int i = 0; i < array.length; i++) { if(array[i].equals(str2)) { count++; System.out.println(array[i]); System.out.println(count); } }//for }//main }//test It looks like you're splitting on "\t" (tab), but your string is " " (space) separated. Try String array[] = str1.split(" "); instead.
Do NOT use "\t" but use " " instead, and it works.....
"\t" will be useful only if you are have "tab" used instead of space.
Try this now..
public class T { public static void main(String[] args) { String str1 = "abc def ghi abc ded abc ghi"; String str2 = "ghi"; int count = 0; String array[] = str1.split(" "); for(int i = 0; i < array.length; i++) { if(array[i].equals(str2)) { count++; System.out.println(array[i]); System.out.println(count); } }//for }//main }//test String has contains method it help to find out the occurance of an item . in your case str1.contains(str2)
If you don't want to use split, you can use the StringTokenizer class also. http://docs.oracle.com/javase/1.4.2/docs/api/java/util/StringTokenizer.html I find this most useful. You can create a StringTokenizer for each string like this.
StringTokenizer st1 = new StringTokenizer(str1," ");
The " " after the str1 indicates which things to parse by. So if you wanted to parse by a comma, dash, number, letter, anything, just put it there!
Then create an array based on the number of tokens it finds like this:
String[] array1 = new String[st1.countTokens()]; Fill the array like this:
for(int i=0;i<st1.countTokens();i++) { array1[i]=st1.nextToken(); } You could similarly do this with str2, and compare this way! This is just a different way to do this as you asked. Otherwise, changing the "/t" to " " will work with the split as said in other answers.
Hope this helps!
split(" "), as you want to split theStringat its white spaces and not at tabbed spaces