I was about to initialize a char array inside a class as
class a{ char a[25]; }; a::a(){ a[] = {'a','b','c'}; } but gives compile time error.
- 1You can initialize it in class constructor.Arun Jain– Arun Jain2012-07-25 06:27:06 +00:00Commented Jul 25, 2012 at 6:27
- My answer on this other question might help you.Qaz– Qaz2012-07-25 06:27:28 +00:00Commented Jul 25, 2012 at 6:27
- @ArunJain thats what im doing..isnt it..second part a(){}??Shashi Bhushan– Shashi Bhushan2012-07-25 06:29:28 +00:00Commented Jul 25, 2012 at 6:29
- Does it have to be char array? Can't you use std::string?Ivaylo Strandjev– Ivaylo Strandjev2012-07-25 06:29:49 +00:00Commented Jul 25, 2012 at 6:29
- char array it has to be.Shashi Bhushan– Shashi Bhushan2012-07-25 06:30:15 +00:00Commented Jul 25, 2012 at 6:30
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2 Answers
If your compiler supports the C++11 feature, you can do it like this:
a::a() :arr({'a','b','c'}) {} Otherwise, you'll have to do it manually, or you can use a function like memcpy:
a::a() { memcpy(arr,"abc",3); // The other initialization method will fill the rest in with 0, // I don't know if that's important, but: std::fill(arr + 3, arr + 25, '\0'); } Or, as suggested by ephemient:
a::a() { strncpy(arr, "abc", 25); } 1 Comment
ephemient
Another possibility: when
strncpy is available, it always pads with \0 to fill -- strncpy(a, "abc", 25) will write 25 bytes, the last 22 of which are NUL.class LexerP { public: char header[5]; void h(); void echo(){printf(" salut les gars ...\n \n");}; }; void LexerP::h() { int i=0; int j=0; char headM[5] ={0x07,0x0A,0x05,0x00,0x05}; /* for (i=0;i<strlen(this->header);i++) header[i]=headM[i];*/ strcpy(this->header,headM) }; main() { LexerP *M=new (LexerP); M->echo(); M->h(); return 0; } 