Java: How to call super().super() in overridden method (grandparent method) [duplicate]

Question

Possible Duplicate:
Why is super.super.method(); not allowed in Java?

I have 3 classes they inherit from each other as follows:

A ↳ B ↳ C

Inside each class I have the following method:

protected void foo() { ... }

Inside class C I want to call foo from class A without calling foo in B:

protected void foo() { // This doesn't work, I get the following compile time error: // Constructor call must be the first statement in a constructor super().super().foo(); }

EDIT
Some Context Info:
Class B is an actual class we use. Class C is a unit test class, it has some modifications. foo method inside B does some things we don't want so we override it inside C. However foo in class A is useful and needs to be called.

Take a look at this topic stackoverflow.com/questions/586363/… — Pr0gr4mm3r
– Pr0gr4mm3r, Commented Aug 13, 2012 at 14:07

assylias · Accepted Answer · 2012-08-13 14:07:13Z

To call a method in a super class, you use super.foo(), not super().foo(). super() calls the constructor of the parent class.
There is no way to call super.super.foo(). You can add a call to super.foo() in class B, so that calling super.foo() in C, will call super.foo() in B which in turn will call foo() in A.

Romain · Accepted Answer · 2012-08-13 14:07:03Z

It's not possible in Java. You'd need to rely on B providing you with an explicit way to access to A's foo.

Collectives™ on Stack Overflow

Java: How to call super().super() in overridden method (grandparent method) [duplicate]

2 Answers 2

Comments

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Linked

Related