class a { void show() { } class b extends a { void show() { } class c extends b { //how to call show method of class a } } } Does anyone know how I can call method of class a from class c using super keyword
- Please format that code. Also, what language are you using? Assuming pseudocode, I would say that "show()" should be inherited to class "C", so it should be callable anyway. Assuming that "show()" in class "A" is private, it depends on the language - assuming C#, there would be no way to call it from class "A" (since the method is private).alexander.biskop– alexander.biskop2015-02-19 09:41:16 +00:00Commented Feb 19, 2015 at 9:41
- Seems duplicate: stackoverflow.com/q/11935895/11226492 stackoverflow.com/q/586363/11226492Aincvy– Aincvy2024-01-29 02:30:11 +00:00Commented Jan 29, 2024 at 2:30
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1 Answer
class A { void show() { System.out.println("A"); } } class B extends A { void show() { System.out.println("B"); } } class C extends B { void show() { super.show(); } } The above code will display "B" when class C object is invoked. In your case, there can be 2 options:
- C extends A - This will let super.show() in show method of class C display "A".
- Add super.show() in show method of class B so that show method of class C displays both "B" and "A".
There is no way to call super class methods which are higher than level 1.
