This is how my code looks and I get an error, while using Popen
test.py
import subprocess import sys def test(jobname): print jobname p=subprocess.Popen([sys.executable,jobname,parm1='test',parm2='test1']) if __name__ == "__main__": test(r'C:\Python27\test1.py') test1.py
def test1(parm1,parm2): print 'test1',parm1 if __name__ = '__main__': test1(parm1='',parm2='') Error
Syntax error
In test1.py:
You need two equal signs in :
if __name__ = '__main__': Use instead
if __name__ == '__main__': since you want to compare the value of __name__ with the string '__main__', not assign a value to __name__.
In test.py:
parm1='test' is a SyntaxError. You can not to assign a value to a variable in the middle of a list:
p=subprocess.Popen([sys.executable,jobname,parm1='test',parm2='test1']) It appears you want to feed different values for parm1 and parm2 into the function test1.test1. You can not do that by calling python test1.py since there parm1='' and parm2='' are hard-coded there.
When you want to run a non-Python script from Python, use subprocess. But when you want to run Python functions in a subprocess, use multiprocessing:
import multiprocessing as mp import test1 def test(function, *args, **kwargs): print(function.__name__) proc = mp.Process(target = function, args = args, kwargs = kwargs) proc.start() proc.join() # wait for proc to end if __name__ == '__main__': test(test1.test1, parm1 = 'test', parm2 = 'test1') 
