why does 2^0 return 2 in java [duplicate]

Question

Possible Duplicate:
What does the ^ operator do in Java?
The power ^ in Java?

I am sorry if this is a duplicate, but i didn´t found anything in SO.

So can someone explaint me why

 System.out.println((2^0));

this does return 2?

i was expecting a 1.

Suggested search in the future: x operators. Replace x with the language in question: it will cover most questions of "Why/What does a <op> b ..?". — user166390
– user166390, Commented Dec 27, 2012 at 10:38

duffymo · Accepted Answer · 2012-12-27 10:37:18Z

Because the ^ operator does not mean "raise 2 to the 0th power". It's a bitwise exclusive OR operator.

In order to do that, your code should look like this:

double one = Math.pow(2.0, 0.0); // Silly, but you can do it.

Don't be surprised if the answer comes out to something that's not exactly 1.0. You'll need to know about how floating point numbers work.

rekire · Accepted Answer · 2012-12-27 10:37:26Z

6

The ^ sign means XOR and not pow. Try Math.Pow(2.0, 0.0) instead.

answered Dec 27, 2012 at 10:37

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Comments

Saty · Accepted Answer · 2012-12-27 10:42:20Z

4

^ in Java is Bitwise exclusive-OR. so 2(1 0) ^(XOR) 0(0 0) =1 0 ie 2 !!! Got it?

answered Dec 27, 2012 at 10:42

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