I have multiple variables like $soft0 , $soft1 , $soft2 , $soft3 , $soft4 , $soft5 and also like $fo0 , $fo1 , $fo2 , $fo3 , $fo4 , $fo5 but if i want to apply a if condition here then it showing error. Code:
for ($i=0; $i<=29; $i++) { $soft$i = str_replace(" ", "+", $fo$i); // this line showing an error $link_f_u = $html->find('h3', 0); $keyy = $link_f_u->plaintext; if ($soft$i==$keyy){ continue; } else { publish($soft$i); } } Any ideas to modify this code?
This will fix your error, but I would highly recommend you take a look at arrays: http://php.net/manual/en/language.types.array.php
for($i=0;$i<=29;$i++){ $softVarName = "soft" . $i; $foVarName = "fo" . $i; $$softVarName = str_replace(" ", "+", $$foVarName); $link_f_u = $html->find('h3', 0); $keyy = $link_f_u->plaintext; if ($$softVarName==$keyy){ continue; } else { publish($$softVarName); } } 
This should fix the issue.
for($i=0;$i<=29;$i++){ ${'soft' . $i} = str_replace(" ", "+", ${'fo' . $i}); // this line showing an error $link_f_u = $html->find('h3', 0); $keyy = $link_f_u->plaintext; if (${'soft' . $i} == $keyy){ continue; } else { publish(${'soft' . $i}); } } 
$soft{$i} will not work. See: $soft1 = "test"; $i = 1; echo $soft{$i}; Will produce the error Undefined variable: soft
change $soft0 ... $soft10 to arrays looking like $soft[0] .. $soft[10]. You can then use count() in your for loop:
for($i=0;$i<=count($soft);$i++){ $soft[$i] = str_replace(" ", "+", $fo[$i]); $link_f_u = $html->find('h3', 0); $keyy = $link_f_u->plaintext; if ($soft[$i]==$keyy){ continue; } else { publish($soft[$i]); } } You can also use double dollar sign, however this is messy and can result in errors that are hard to catch.
$soft_name = 'soft'.$i; $fo_name = 'fo'.$i; $$soft_name = str_replace(" ", "+", $$fo_name); 