Differentiate between methods in a class based on the naming convention?

Question

Here is the scenario:

I have a class with no predetermined amount of methods. Some will be function actionName and others will be called function filterName where "filter" and "action" will define what type of method they are and "Name" can be anything.

In my __construct() I want to:

$methods = get_class_methods($this); foreach ( $methods as $method ) { if ( $method == 'action' ) $this->DoSomething( $this->{$method}() ); if ( $method == 'filter' ) $this->DoSomethingElse( $this->{$method}() ); }

How can I achieve this without using any type of string or reg expressions?

I am also open to using an alternative to get_class_methods(). But remember I will never know how many "action" or "filter" methods exists.

Sébastien Renauld · Accepted Answer · 2013-04-10 17:53:47Z

1

if (substr($method,0,6) == "action") { } if (substr($method,0,6) == "filter") { }

I'm simply checking the first six character-chain on the name of the function for the keywords. Be warned - too many keywords will kill the performance of this.

answered Apr 10, 2013 at 17:53

Sébastien Renauld

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3 Comments

Kirill Fuchs Over a year ago

I might be reading this wrong but the main reason I do not want to use any type of str search because if you look at Benchmarks it gives off the impression that just 80 loops takes about 1 second. That to me sounds like a hell of a-lot of over head... In my example I very well could have over 100 methods. It's something I can never predict or know.

Sébastien Renauld Over a year ago

In terms of "other methods", I have rarely seen a method able to discern strings without actually using any kind of string comparison to do so. There are no handy flags that you could use, so the only thing left is a lookup table :-(

Kirill Fuchs Over a year ago

Basically I want to do function {type}name () {} and then if ( functionType($fName) == 'action' ) {...}

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