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arr2=[0]*(x^2) # x is the length of the list data for i in range(x): arr2[i]=data[i].split(',')#data is a list like:['1,2','3,4'] arr2=np.array(arr2) A=np.asmatrix(arr2) print A.I

This is giving error as setting an array element with a sequence

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  • 2
    Please give some context about what you're trying to do and give a specific question related to the problem you're having. Commented Jul 3, 2013 at 13:49
  • I need to have a matrix to take out its inverse Commented Jul 3, 2013 at 14:08
  • @abcdxx did you check my answer? Commented Jul 3, 2013 at 14:12
  • @abcdxx You don't need to create the intermediate array to create the matrix, check the answer below... Commented Jul 3, 2013 at 16:44

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Something like this:

>>> data = ['1,2','3,4'] >>> arr2=[ map(float,x.split(',')) for x in data] >>> arr2 = np.asarray(arr2) >>> A = np.asmatrix(arr2) >>> A.I matrix([[-2. , 1. ], [ 1.5, -0.5]])
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