Access Laravel route from controller or pass parameter to controller from route

Question

I have four routes on my picture gallery app. They all do the same: query the database and render pictures. The only difference between them is the order of the records. For example:

http://example.com/favorites : shows pics ordered by favorites http://example.com/random : shows pics ordered by random http://example.com/votes : shows pics ordered by votes http://example.com/views : shows pics ordered by views

For this, I want to use ONE action in my gallery controller and pass the order as a parameter.

I know I can create this route:

Route::get('/{orderby}', 'GalleryController@showPics')

Then get the parameter from the controller:

class GalleryController extends BaseController { public function showPics($orderby) { //query model ordering by $orderby and render the view } }

The problem is I don't want to capture example.com/whatever, only those four specific routes.

Is it there a way to pass a parameter to a controller action from the route. Or, alternatively, to read the current accessed route from the controller?

Rubens Mariuzzo · Accepted Answer · 2013-08-13 13:55:50Z

You can add a parameter constraint to your route that limits the possible values with a regular expression as show below.

Route::get('/{orderby}', 'GalleryController@showPics') ->where('orderBy', 'favorite|random|vote|view');

And as you know, you will get those values in the mapped controller action:

public function showPics($orderby) { dd($orderby); // favorite, random, vote or view. }

You can read more about parameter route constraint in the docs: http://laravel.com/docs/routing#route-parameters

My particular problem was not passing a variable to the controller method as in: public function showPics($orderby) { .. }. I was trying to get the value of the variable indirectly within the method like so: Input::get('orderby'); and this didn't work. The way you set up the route, however, did work for me similarly as well.

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