increment operator ++i does not cause an error in python [duplicate]

Question

Since the increment operator ++ is not supported in python, why doesn't it cause an error when prefixing a variable. Example:

i = 3 ++i

prints 3 on the interactive console. Why is that?

alecxe · Accepted Answer · 2013-08-29 09:06:33Z

5

Take a look - it's just a sign:

>>> i = 3 >>> +i 3 >>> ++i 3 >>> +++i 3 >>> -i -3 >>> --i 3 >>> ---i -3

answered Aug 29, 2013 at 9:06

476k127 gold badges1.1k silver badges1.2k bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Just figured it out a few secs ago. Thanks and answer accepted.

Rohit Jain · Accepted Answer · 2013-08-29 09:07:37Z

3

Python treats ++i as +(+i), that would compile fine, and print the same value as of i.

answered Aug 29, 2013 at 9:07

214k45 gold badges419 silver badges534 bronze badges