var myarray = []; var result1 = myarray[0]; var result2 = myarray[1]; var result3 ....etc... Selecting first is easy, cause it's just 0. How do I put the last one into a var? It seems like such a simple question but I must have been googling wrong cause I could not find any answer that worked.
var last = myarray[myarray.length - 1]; 
myarray.length returns the length of array and as the elements have started from 0 subtracting one from it will give the index of last element
var lastresult = myarray[myarray.length - 1]; 
var lastelement = myarray[myarray.length - 1] One way would be to do something like this
var lastElement = myArray[myarray.length-1] Don't overthink. Arrays may be 0 indexed in javascript but that just means that the last index has to be the length of the array -1.
Just this:
var lastResult = myarray[myarray.length - 1]; You can create prototype to do this more simple. For example:
if (!Array.prototype.last){ Array.prototype.last = function(){ return this[this.length - 1]; }; }; and than use
myarray.last(); 
last = lastInArray.call(arr,arr); still have you method use thisyou could use array prototype method .pop() but that will remove last item from array:
var lastElement = myarray.pop(); Or wrap array in jq object:
var lastElement = $(myarray).get(-1); I could be wrong about this, so perhaps someone else can tell me if I'm right or wrong, but can't you just do:
var last = myArray[-1] ?
EDIT: I'm wrong. Ignore me.
Also, out of curiosity, would it be faster to use
var lastelement = myarray[myarray.length - 1]; or
var lastelement = myarray.reverse[0]; ?
so perhaps someone else can tell me if I'm right or wrong What happens when you try this yourself? :)undefined as -1 is not a valid index of a JavaScript array.
$(array).get(-1);