Unable to use StringBuilder to concatenate chars to String

Question

BThis is my code:

public static void main(String[] args) { String teacherName = "Benjamin Brown"; int teacherSecondInitialIndex = (teacherName.indexOf(" ") + 1); String teacherInitials = new StringBuilder(teacherName.charAt(0)).append(teacherName.charAt(teacherSecondInitialIndex)).toString(); System.out.println(teacherInitials); }

I want to print out the initials of teacherName, which would be "BB". But only "B" is being printed out. What is the issue?

Why is it "BG" and not "BB" ?

AntonH
– AntonH

2014-03-04 23:09:30 +00:00
Commented Mar 4, 2014 at 23:09 — AntonH
– AntonH, Commented Mar 4, 2014 at 23:09
My bad, you're right. Edited it.

Hen Sapir
– Hen Sapir

2014-03-04 23:13:43 +00:00
Commented Mar 4, 2014 at 23:13 — Hen Sapir
– Hen Sapir, Commented Mar 4, 2014 at 23:13

Sotirios Delimanolis · Accepted Answer · 2014-03-04 23:11:34Z

This constructor

new StringBuilder(teacherName.charAt(0))

accepts an int. So the char value you are passing is being widened and used as the StringBuilder capacity, not as the first char in the underlying String.

Create an empty StringBuilder and append two chars.

String teacherInitials = new StringBuilder() .append(teacherName.charAt(0)) .append(teacherName.charAt(teacherSecondInitialIndex)) .toString();

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