Template Class with function pointer doesn't accept specialisation

Question

I am trying to create a template so that I can have a function pointer (for a callback function) that accepts both a Class as a base for member functions as well as as having a way to have globally defined functions.

At the moment I have

template <class c> struct Callback { typedef void(c::*callback)(void); };

Which works and will allow me to use Callback::callback as a type

However when I try and add a specific implementation such as:

class VOIDCLASS { void * void_ptr; }; // Callback template declaration as above here template <VOIDCLASS> struct Callback { typedef void(*callback)(void); };

I get a compiler error : error C3855: 'Callback': template parameter 'c' is incompatible with the declaration This is using Visual Studio 2013 with a platform tool-set of v110(VS2012) and Windows 8.1

jrok · Accepted Answer · 2014-03-18 18:34:20Z

2

An explicit specialization is written like this:

template<> struct Callback<VOIDCLASS> { typedef void(*callback)(void); };

answered Mar 18, 2014 at 18:34

jrok

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Mark B · Accepted Answer · 2014-03-18 18:34:28Z

1

I think you meant:

template <> struct Callback<VOIDCLASS> { typedef void(*callback)(void); };

answered Mar 18, 2014 at 18:34

Mark B

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