Get file name only (without extension and directory) from file path

Question

What I have:

import os import ntpath def fetch_name(filepath): return os.path.splitext(ntpath.basename(filepath))[0] a = u'E:\That is some string over here\news_20.03_07.30_10 .m2t' b = u'E:\And here is some string too\Logo_TimeBuffer.m2t.mpg' fetch_name(a) >>u'That is some string over here\news_20.03_07.30_10 ' # wrong! fetch_name(b) >>u'Logo_TimeBuffer.m2t' # wrong!

What I need:

fetch_name(a) >>u'news_20.03_07.30_10 ' fetch_name(b) >>u'Logo_TimeBuffer'

Use raw strings for Windows file names, as the backslashes can be converted into other things...; as in r'E:\That is some string over here\news_20.03_07.30_10 .m2t' — EvertW
– EvertW, Commented Apr 22, 2014 at 8:09
How exactly do you want to differentiate between a file extension and a normal .? Do you want to treat all three-character suffixes delimited by . as extensions? — merlin2011
– merlin2011, Commented Apr 22, 2014 at 8:12
Your code works exactly as it should. In example a, the \n is not treated as a backslash character because it is a newline character. In example b, the extension is .mpg, which is properly removed. A file can never have more than one extension, or an extension containing a period. — EvertW
– EvertW, Commented Apr 22, 2014 at 8:20
@aspect_mkn8rd, Then you already have your solution. :) Just download or create a list of extensions that you consider official, and strip any suffix off your filename that is inside that list. By the way, I will write a program tomorrow that uses .bla.mpg as an extension. :P — merlin2011
– merlin2011, Commented Apr 22, 2014 at 8:21
okay, seems like I get all the situation clearly. Now can you please post these last two comments as answers? I wanna give you two guys rep for your effort and end the question. :) — Bruno Gelb
– Bruno Gelb, Commented Apr 22, 2014 at 8:23

EvertW · Accepted Answer · 2014-04-22 09:40:08Z

Your code works exactly as it should. In example a, the \n is not treated as a backslash character because it is a newline character. In example b, the extension is .mpg, which is properly removed. A file can never have more than one extension, or an extension containing a period.

To only get the bit before the first period, you could use ntpath.basename(filepath).split('.')[0], but this is probably NOT what you want as it is perfectly legal for filenames to contain periods.

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