I got title and url. How to make link?

Question

I have news titles and urls. How to make it to the link?

This is how I extract titles and urls:

def Save(request): news = [] links = [] url ="http://www.basketnews.lt/lygos/59-nacionaline-krepsinio-asociacija/2013/naujienos.html" r = requests.get(url) soup = BeautifulSoup(r.content) nba = soup.select('div.title > a') for i in reversed(nba): news.append(i.text) # Here I have list of titles links.append(i["href"]) # list of urls # Here I'm saving that info to my model. Ignore it save_it = Naujienos(title = i.text, url = "Basketnews.lt" + i['href']) # save_it.save() return render(request, 'Titles.html', {'news': news, "links": links})

Here is my HTML:

{% for i in news%} {% for o in links%} <a href={{o}}>{{i}}</a> {% endfor %} {% endfor %}

As I suppose you already know that this kind of making links is worng. So, what is the right way to do it?

is it not working? What's error? <a href={{ o }}>{{ i }}</a> should work — felipsmartins
– felipsmartins, Commented May 18, 2014 at 17:53

Community · Accepted Answer · 2017-05-23 11:50:23Z

How about trying something like that?

from collections import namedtuple Link = namedtuple('Link', ['title', 'url'], verbose=True) def Save(request): ... for i in reversed(nba): links.append(Link(title=i.text, url=i["href"])) # list of urls ...

Then template would be:

{% for link in links %} <a href="{{link.url}}">{{link.title}}</a> {% endfor %}

And if you want to stick with two lists, then you should have a glance at this question.

Collectives™ on Stack Overflow

I got title and url. How to make link?

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related