Using Preferences API to save path?

Question

I'm trying use Preferences API to save a path to file in regedit. It is works but the value of path is not saved correctly.

I'm trying this.

public class ImageLogoPreference { private final String path = "configs"; private Preferences node; public ImageLogoPreference(){ node = Preferences.userRoot().node(path); } public void setImageLogo(){ node.put("logo", "\\IguanaSistemas\\IguanaFight\\imagens\\logo.png"); } public String getImageLogo(){ String logo = node.get("logo", "image"); return logo; } }

At register save this: ///Iguana/Sistemas///Iguana/Fight//imagens//logo.png

enter image description here Any idea ?

The API is auto formatting the value based on it's requirements, same thing happens to Properties when they are saved. — MadProgrammer
– MadProgrammer, Commented Aug 19, 2014 at 0:06

Xabster · Accepted Answer · 2014-08-18 23:48:51Z

Doesn't matter.

Just get it in your Java program. You don't have a problem.

 Preferences node = Preferences.userRoot().node("config"); //node.put("logo", "\\IguanaSistemas\\IguanaFight\\imagens\\logo.png"); String s = node.get("logo", "blah"); System.out.println(s);

Prints the correct string.

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