Single variable inside an if statement

Question

I basically want a way to write an if statement with only one variable in it, like:

$var = "$foo == 'bar'"; if ($var) { // do code }

Or to put it more descriptively, Instead of:

$run_list = array("normal"); if (!empty("extras")) array_push($run_list, "extras"); foreach ($run_list as $iteration) { if ($iteration == "normal") { if ($array1 == $array2) { # do 125 lines of code here } // Will not always be True (may only iterate once) } elseif ($iteration == "extras") { if ($array1 != $array2) { # do exact same 125 lines of code here } } }

How could I do something similar to this, but that actually works:

$run_list = array("normal"); if (!empty("extras")) array_push($run_list, "extras"); foreach ($run_list as $iteration) { if ($iteration = "normal") { $if_statement = "$array1 == $array2"; } elseif ($iteration = "extras") { $if_statement = "$array1 != $array2"; } if ($if_statement) { # do 125 lines of code here } }

And I don't want to put the 125 lines of code into a function because they contain dozens of variables set earlier in the code and I don't really want to create a function where I have to pass in dozens of variables for it to work.

if($iteration == "normal") why do you want to change that into something complicated? — Hanky Panky
– Hanky Panky, Commented Nov 22, 2014 at 15:25

Clément Prévost · Accepted Answer · 2014-11-22 15:23:44Z

You might want to merge your boolean expressions here

$run_list = array("normal"); if (!empty("extras")) array_push($run_list, "extras"); foreach ($run_list as $iteration) { if ( ($iteration == "normal" && array1 == $array2) || ($iteration == "extras" && $array1 != $array2) ) { # do 125 lines of code here } }

Tom · Accepted Answer · 2014-11-22 15:41:36Z

You could first create a boolean to later test in the condition like so:

 $conditional = $iteration === "normal";

And then later test that conditional:

if($conditional){ //execute code }

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