popen not forwarding args correctly - Python

Question

I am using Raspbian and attempting to run a very simple cmd using python with the popen function. I am very new to linux and python

from subprocess import Popen, PIPE po = Popen(['airmon-ng', 'start wlan0 10'], stdin=PIPE, stdout=PIPE, stderr=PIPE) proc = Popen(args, stdout=PIPE, stderr=PIPE) out, err = proc.communicate() out

returns

'\n\nusage: airmon-ng <start|stop|check> <interface> [channel or frequency]\n\n'

The error msg returned can be created outside of the popen function when running only airmon-ng without parameters, which makes me believe that popen is not forwarding the args correctly.

falsetru · Accepted Answer · 2015-01-01 02:15:06Z

4

You need to separate comamnd line arguments correctly; start, wlan0, 10 should be separated command line arguments:

proc = Popen(['airmon-ng', 'start', 'wlan0', '10'], stdin=PIPE, stdout=PIPE, stderr=PIPE) out, err = proc.communicate() print(out)

The way in the question is like invoking the command as follow in the shell:

airmon-ng 'start wlan0 10'

which is different from:

airmon-ng start wlan0 10

answered Jan 1, 2015 at 2:15

falsetru

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3 Comments

Eevee Over a year ago

note that the whole point of passing a list of parameters is that you've already split them up :)

falsetru Over a year ago

@Eevee, Sorry, I don't understand what you mean.

Eevee Over a year ago

directed at the asker — when you use the shell, it just sees the single string "airmon-ng start wlan0 10" and now needs to split it on whitespace etc. using a list (a data structure) ought to mean you've already done that work.

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