OS version IF statement

Question

I am working with windows 7 and 8.1 machines. I would like to implement a PowerShell script to detect the OS and install a program based on the result.

So far I can get the OS but I get caught in the IF statement.

$Win7="6.1.7601" $Win8="Not tested yet" $Version=(Get-WmiObject win32_operatingsystem).version write-host Your windows version is $version. if(!($version="6.1.7601")) {skip} else {Install file}

I am trying to skip this script and return to a main script if the OS is not win7 otherwise it should install the files needed. Any help would be much appreciated.

Do you mean -eq there?

Etan Reisner
– Etan Reisner

2015-04-29 15:56:35 +00:00
Commented Apr 29, 2015 at 15:56 — Etan Reisner
– Etan Reisner, Commented Apr 29, 2015 at 15:56

Tony Hinkle · Accepted Answer · 2015-04-29 16:00:05Z

1

The = operator is used to set the value of something. You need to use the -eq operator, which compares objects.

if(!($version -eq "6.1.7601"))

answered Apr 29, 2015 at 16:00

Tony Hinkle

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3 Comments

Brandon Ramos Over a year ago

Thanks for that. Things run much smoother now

Ansgar Wiechers Over a year ago

I'd recommend using -ne instead of !(-eq).

n0rd Over a year ago

I'd recommend excluding build number from comparison. I.e. check that version starts with 6.1 only.

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