Windows subprocess with arguments

Question

I need to run pdb2mdb.exe utility, and pass DLL file as argument.

After long googling, and playing with various call/Popen - I still can't find solution...

Here is last code:

def pdb2mdb(logger, modsrcdll): os.chdir("C:\\Program Files (x86)\\Unity\\Editor\\Data\\MonoBleedingEdge\\lib\\mono\\4.0\\") subprocess.call("pdb2mdb.exe %s" % modsrcdll)

But - this way pdb2mdb.exe don't want accept argument, and prints it's help:

Copy file d:\***.dll to C:\cloudlibrary\data Copy file D:\***.dll.xml to C:\cloudlibrary\data PDP FOUND pdbexe found Mono pdb to mdb debug symbol store converter Usage: pdb2mdb assembly

Without os.chdir() - it can't parse C:\\Program Files (x86) at all...

I have used subprocess.call() earlier under Linux, and never had such problems, for example:

subprocess.call('ls -l %s | grep -v total' % self.path, shell=True)

Paths with embedded space characters have to be quoted with ". i.e. subprocess.call('pdb2mdb.exe "%s"' % modsrcdll). — martineau
– martineau, Commented Jun 5, 2015 at 12:27

ρss · Accepted Answer · 2015-06-05 11:50:26Z

You can try subprocess.Popen

p = subprocess.Popen("pdb2mdb.exe modsrcdll", stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True) out, err = p.communicate() print out print err

Example: The code below will open notepad.exe from C:\\Windows\\System32 and give the file test.txtas an argument. The same might work for your .dll

import subprocess def myFunc(): p = subprocess.Popen("C:\\Windows\\System32\\notepad.exe c:\\Users\\admin\\Desktop\\test.txt", stdout=subprocess.PIPE, stderr=subprocess.PIPE) out, err = p.communicate() print out print err myFunc()

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