Function overloading with template

Question

I have the following code.

#include <iostream> using namespace std; void print(int& number){ cout<<"\nIn Lvalue\n"; } void print(int&& number){ cout<<"\nIn Rvalue\n"; } int main(int argc,char** argv){ int n=10; print(n); print(20); }

It works fine. But I want to make a function template so that it accepts both lvalues and rvalues. Can anyone suggest how to do it?

Dimitrios Bouzas · Accepted Answer · 2015-06-10 21:57:17Z

1

Unless you want to change the input argument a const lvalue reference will do the job because rvalue references can bind to const lvalue references:

void print(int const &number) { ... }

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Nevertheless, You could just:

template<typename T> void print(T &&number) { ... }

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answered Jun 10, 2015 at 21:57

Dimitrios Bouzas

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5 Comments

01000001 Over a year ago

This is perfectly working. But what if i want to have two saperate print functions?? Or is it stupid thing to do??

Dimitrios Bouzas Over a year ago

If you want to have two separate print functions then you should have two overloads as in your example. However, from a practical point of view if you only want to print (i.e., not alter the input argument), a single function with input argument a const lvalue reference is sufficient.

01000001 Over a year ago

I am trying to have two saperate templates for both print functions one with T& and other with T&& but its not working.

Dimitrios Bouzas Over a year ago

Yeap, with templates won't work cause the compiler due to certain C++ standard rules can't distinguish between the two overloads.

01000001 Over a year ago

Then i guess i will have to live with only one print.. Anyway thank you so much. :) :)

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